Answer:
option . D
Increase in temperature
is an indicator of a chemical reaction
hope it helps
We assume that the given gas, NO2, is an ideal gas such that we will be able to use the equation,
n/V = P/RT
where n is the number of moles, V is volume, P is pressure, R is gas constant, and T is temperature in kelvin. Substituting the known values,
n/V = (1 atm) / (37 + 273)(0.0821 L.atm/mol.K)
n/V = 0.039 mol/L
Converting this to density by multiplying the value with the molar mass,
density = (0.039 mol/L) x (46 g/mol) = 1.8 g/L
Answer: Tens place.
Step-by-step explanation: hmm wait one moment
Carboxylic acids: considered as weak acids due to they ionize in solution to give -COO⁻ and H⁺, they are abundant in nature, they can form intermolecular hydrogen bonds so they exist as dimers (remember that alcohols also can form hydrogen bonds).
- Acids have higher boiling and melting points than corresponding molar mass compounds due to the formation of hydrogen bond
- Aromatic carboxylic acids are solids in nature at room temperature
Answer:
Circuit 4
Explanation:
To know the correct answer to the question given above, we shall determine the current in each circuit. This can be obtained as follow:
For circuit 1:
Resistance (R) = 0.5 ohms
Voltage (V) = 20 V
Current (I) =?
V = IR
20 = I × 0.5
Divide both side by 0.5
I = 20 / 0.5
I = 40 A
For circuit 2:
Resistance (R) = 0.5 ohms
Voltage (V) = 40 V
Current (I) =?
V = IR
40 = I × 0.5
Divide both side by 0.5
I = 40 / 0.5
I = 80 A
For circuit 3:
Resistance (R) = 0.25 ohms
Voltage (V) = 40 V
Current (I) =?
V = IR
40 = I × 0.25
Divide both side by 0.25
I = 40 / 0.25
I = 160 A
For circuit 4:
Resistance (R) = 0.25 ohms
Voltage (V) = 60 V
Current (I) =?
V = IR
60 = I × 0.25
Divide both side by 0.25
I = 60 / 0.25
I = 240 A
SUMMARY
Circuit >>>>>> Current
1 >>>>>>>>>>> 40 A
2 >>>>>>>>>>> 80 A
3 >>>>>>>>>>> 160 A
4 >>>>>>>>>>> 240 A
From the above calculation, circuit 4 has the greatest electric current.
