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Grace [21]
3 years ago
15

Write a balanced molecular equation and a net ionic equation for the reaction that occurs when magnesium hydroxide reacts with a

hydrochloric acid solution. Express your answers as chemical equations separated by a comma. Identify all of the phases in your answer.
Chemistry
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

Balanced molecular equation and net ionic equation have been shown below.

Explanation:

Mg(OH)_{2} is a weak base as it does not dissociate completely in water. HCl is a strong acid as it dissociates completely in water.

Reaction between Mg(OH)_{2} and HCl is an example of acid-base reaction. Here a salt MgCl_{2} is formed along with H_{2}O.

Balanced molecular equation:

Mg(OH)_{2}(aq.)+2HCl(aq.)\rightarrow MgCl_{2}(aq.)+2H_{2}O(l)

To write net ionic equation, spectator ions are to be removed from both side of total ionic equation. Here Cl^{-} is the spectator ion.

Total ionic equation:

Mg(OH)_{2}(aq.)+2H^{+}(aq.)+2Cl^{-}(aq.)\rightarrow Mg^{2+}(aq.)+2Cl^{-}(aq.)+2H_{2}O(l)

Net ionic equation:

Mg(OH)_{2}(aq.)+2H^{+}(aq.)\rightarrow Mg^{2+}(aq.)+2H_{2}O(l)

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The balloon will reach its maximum volume and it will burst.

Given:

  • A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
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To find:

Whether the weather balloon will reach its maximum volume or not.

Solution:

The pressure of the gas in the weather balloon at sea level = P_1=745 torr

1 atm = 760 torr\\P_1=745 torr=\frac{745}{760} torr = 0.980 atm

The volume of the weather balloon at sea level = V_1=65.0L

The temperature of the gas in the weather balloon at sea level:

T_1=25^oC=25+273.15 K=298.15 K

The balloon rises to an altitude.

The pressure of the gas in the weather balloon at the given altitude:

P_2=0.066atm

The volume of the weather balloon at the given altitude = V_2=?

The temperature of the gas in the weather balloon at the given altitude:

T_1=25^oC=25+273.15 K=298.15 K

Using the Combined gas law:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\frac{0.980 atm\times 65.0L}{298.15 K}=\frac{0.066atm\times V_2}{298.15K}\\V_2=\frac{0.980 atm\times 65.0L\times 298.15K}{0.066atm\times 298.15 K}\\=965L

The maximum volume of the weather balloon= V = 835 L

V < V_2

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.

Learn more about the combined gas law:

brainly.com/question/13154969?referrer=searchResults

brainly.com/question/936103?referrer=searchResults

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