Answer:
13.8072 kj
Explanation:
Given data:
Mass of water = 100.0 g
Initial temperature = 4.0 °C
Final temperature = 37.0°C
Specific heat capacity = 4.184 j/g.°C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 37.0°C - 4.0 °C
ΔT = 33.0°C
Q = 100.0 g ×4.184 j/g.°C × 33.0°C
Q = 13807.2 j
Joule to KJ:
13807.2 j × 1kj /1000 j
13.8072 kj
Answer:
I think your answer is either b or c but I think b is more likely to be your answer
It is B that one has the most mass
From the information we have, this block of brown sugar has a volume of 8cm3
The mass of the block is 12. 9 grams.
We need to find out the density of the sugar.
For a solid material the formula for calculating density is given as:
Density = mass / volume
Therefore we simply fit in the above given values into this formula, so:
Density = 12.9 / 8
Density = 1.61
Therefore the density of the block of sugar is 1.61g/ml
The behavior of the water molecules change as the pan of water is heated, As the water is heated, the water molecules move faster and farther apart. The molecules change as the water is heated and the water molecules move faster and farther.<span>
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