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Darya [45]
3 years ago
5

g In animal tissues the rate of conversion of pyruvate to acetyl-CoA is regulated by the ratio of phosphorylated and dephosphory

lated PDH complex. Describe what happens to this reaction when a preparation of rabbit muscle mitochondria containing PDH complex is treated with:
Chemistry
1 answer:
Colt1911 [192]3 years ago
5 0

Answer: seen below.

Explanation: since the different means use in treating rabbit muscle mitochondria containing PDH complex. I will give different reactions that occurs.

The mitochondria preparation responds as follow;

Active pyruvate dehydrogenase (dephosphorylated) is converted to inactive pyruvate dehydrogenase (phosphorylated) and the rate of conversion of pyruvate to acetyl-CoA decreases.

The phosphoryl group on pyruvate dehydrogenase (dephosphorylated) phosphate is removed enzymatically to give active pyruvate dephosphorylated which increases the rate of conversion of pyruvate to acetyl-CoA.

Malonate inhibit succinate dehydrogenase, and citrate accumulates. Accumulation of this citrate inhibits citrate synthase, and acetyl-CoA accumulates. Increased level of this acetyl-CoA inhibits pyruvate dephosphorylated and the rate of conversion of pyruvate to acetyl-CoA decreases.

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All the water on the earth is the same water that has been here since

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Which subatomic particle is located outside the nucleus
Mrac [35]
Electrons is located outside the nucleus
5 0
3 years ago
PLZZZZZZZZZZZZZZZZZZ15. As much as 90 percent of the oxygen in our atmosphere is the result of
vladimir2022 [97]

Answer:

The correct answer is - option D. photosynthesis.

Explanation:

It is shown by the study that most of the atmospheric oxygen comes from the photosynthesis by plants as oxygen is the byproduct of the photosynthesis. Photosynthesis is the process that uses light energy, carbon dioxide, and water to produce food or glucose/sugar and release oxygen as the byproduct.

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7 0
3 years ago
Read 2 more answers
5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
How much sucrose (g) do you need to weight in order to prepare 19.16 g of a 13.1 % (weight percent) solution?
Nonamiya [84]
<span>2.51 grams
   You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication: 19.16g * 0.131 = 2.50996g
   Rounding to 3 significant figures gives 2.51 g.</span>
3 0
3 years ago
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