PLEASE PLEASE please please help with Chemistry!!!!!
1 answer:
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For this question, lets apply Avagadro's law
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
where V-volume, n-number of moles and k - constant
Therefore at 2 instances
where V1 and n1 are for 1st instance
and V2 and n2 are for 2nd instance
therefore
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated
V2 = 2.4 x 5.3 / 3.7
= 3.4 L
Answer is 1st option 3.4 L
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
where V-volume, n-number of moles and k - constant
Therefore at 2 instances
where V1 and n1 are for 1st instance
and V2 and n2 are for 2nd instance
therefore
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated
V2 = 2.4 x 5.3 / 3.7
= 3.4 L
Answer is 1st option 3.4 L
Answer:
Explanation:
The expression for the work done is:
Where,
W is the amount of work done by the gas
R is Gas constant having value = 8.314 J / K mol
T is the temperature
P₁ is the initial pressure
P₂ is the final pressure
Given that:
T = 300 K
P₁ = 10 bar
P₂ = 1 bar
Applying in the equation as: