Answer:
ummmm okay but why tho lol
Answer:
I can't help you, it doesn't indicate what you need
The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
_____
As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
I think I know how to do it
Your equation is:
P₁V₁ = P₂V₂
You Know:
Initial:
P₁ = 84 Pa
V₁ = 336 L
New:
P₂ = ?
V₂ = 216L
Plug this into the equation:
P₁V₁ = P₂V₂
(84 Pa)(336 L) = P₂(216 L) Divide 216 on both sides
130.6666666 = P₂
(if your doing significant figures, you have 2 sig figs)
130 Pa = P₂
Answer:y.5
Step-by-step explanation:5 times 3 = 15/2 = 7.5
