Answer:
(Amplitude) (Correct answer: 1)
(Angular frequency) (Correct answer: 2)
(Phase shift) (Correct answer: 3)
(Vertical shift) (Correct answer: 4)
(Period) (Correct answer: 5)
Step-by-step explanation:
The general form of a sinusoidal function is represented by the following characteristics:
(1)
Where:
- Amplitude.
- Angular frequency.
- Phase shift.
- Vertical shift.
- Independent variable.
- Dependent variable.
In addition, we know that the period associated with the sinusoidal function (
) is:

By direct comparison, we get the following conclusions:
(Amplitude) (Correct answer: 1)
(Angular frequency) (Correct answer: 2)
(Phase shift) (Correct answer: 3)
(Vertical shift) (Correct answer: 4)
(Period) (Correct answer: 5)
Answer:
3₹
Step-by-step explanation:
To print cost is 3₹a manager if company print
Answer:
B) (35, 260)
Step-by-step explanation:
A veterinarian will prescribe an antibiotic to a dog based on its weight. The effective dosage of the antibiotic is given by d ≥ 1∕5w2, where d is dosage in milligrams and w is the dog's weight in pounds. Which of the following ordered pairs gives an effective dosage of antibiotics for a 35-pound dog?
A) (35, 240)
B) (35, 260)
C) (260, 35)
D) (240, 35)
Ordered pairs is composed of pairs, usually an x coordinate and a y coordinate. It refers to a location of a point on the coordinate. It matches numbers to functions or relations.
Given the relation between d is dosage in milligrams and w is the dog's weight in pounds as d ≥ 1∕5w²
For a 35 pound dog (i.e w = 35 pound). The dosage is given as:
d ≥ 1∕5(35)² ≥ 245 milligrams.
For an ordered pair (x, y), x is the independent variable (input) and y is the dependent variable (output).
The dog weight is the independent variable and the dosage is the dependent variable.
From the ordered pairs, the best option is (35, 260) because 260 ≥ 240
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05