Question

* A ball is projected horizontally from the top of

Answer 1

Explanation:

Given

Ball is projected horizontally from a building of height  

time taken to reach ground is given by

(b) Line joining the point of projection and the point where it hits the ground makes an angle of  

From the figure, it can be written

Considering horizontal motion

(c) The vertical velocity with which it strikes the ground is given by

Thus, the ball strikes with a vertical velocity of

Answer 2

Explanation:

Given

Ball is projected horizontally from a building of height $h=19.6\ m$

time taken to reach ground is given by

$\text{Cosidering vertical motion}\\\Rightarrow h=ut+0.5at^2\\\Rightarrow 19.6=0+0.5\times 9.8t^2\\\Rightarrow t^2=4\\\Rightarrow t=2\ s$

(b) Line joining the point of projection and the point where it hits the ground makes an angle of $45^{\circ}$

From the figure, it can be written

$\Rightarrow \tan 45^{\circ}=\dfrac{h}{x}\\\\\Rightarrow x=h\cdot 1\\\Rightarrow x=19.6$

Considering horizontal motion

$\Rightarrow x=u_xt\\\Rightarrow 19.6=u_x\times 4\\\Rightarrow u_x=4.9\ m/s$

(c) The vertical velocity with which it strikes the ground is given by

$\Rightarrow v^2-u_y^2=2as\\\Rightarrow v^2-0=2\times 9.8\times 19.6\\\Rightarrow v=\sqrt{384.16}\\\Rightarrow v=19.6\ m/s$

Thus, the ball strikes with a vertical velocity of $19.6\ m/s$