Answer:
Width = 2
Length = 5
Step-by-step explanation:
let A be the area of the rectangle
L be the length of the rectangle
w be the width of the rectangle
<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’
A = L × w
…………………………………………………
A = L × w
⇔ 10 = (w + 3) × w
⇔ 10 = w² + 3w
⇔ w² + 3w - 10 = 0
<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 = 0 :
Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49
then √Δ = 7
-5 is not valid ,because w represents the width
which must be a positive number
Then w = 2
<u><em>Conclusion</em></u>:
Width = 2
Length = 2 + 3 = 5
Answer:
Step-by-step explanation:
The graph of the equation that will contain the points (2, 3) and (3, 2) is the graph that has a slope value that is equivalent to the slope value of the line running through the two points.
Slope of the line running through (2, 3) and (3, 2):
.
Slope (m) = -1.
The equation, , is given in the slope-intercept form, which means it has a slope value of -1. I.e. the term "-x" is equivalent to -1x. So therefore, the graph of the equation that contains the points (2, 3) and (3, 2) is .
I don’t know sorry I just need the points
P=2(l+w)
190=2[(2l+5)+l)
190=4l+10+2l
190=6l+10
180=6l
l=30
190=2(30+w)
190=60+2w
130=2w
w=65
The width of the rectangle is 65.
Method 1.
Use the formula of a distance between two points:
We have
substitute
Answer: 10
Method 2
Look at the picture.
Use the Pythagorean theorem:
Answer: 10
