A ball rolling down a hill was displaced 19.6 m while uniformly accelerating from rest. If the final velocity was 5.00m/s what w

Question

3 years ago

9

as the rate of acceleration

1 answer:

poizon [28] · Answer 1 · 2022-06-07T20:50:28+03:00

The rate of acceleration is $0.64 m/s^2$

Explanation:

Since the ball is moving at constant acceleration, we can solve the problem by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the ball in this problem,

u = 0

v = 5.00 m/s

s = 19.6 m

Solving for a, we find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{(5.00)^2-0}{2(19.6)}=0.64 m/s^2$

Learn more about acceleration:

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