The acceleration of the bike is
Explanation:
We can solve this problem by using Newton's second law of motion, which states that:
where
F is the net force on an object
m is the mass of the object
a is its acceleration
For the bike in this problem, we have
F = 175 N is the net force
m = 50 kg is the mass
And solving for a, we find the acceleration:
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Answer:
0.187 m
Explanation:
We'll begin by calculating the acceleration of the ball. This can be obtained as follow:
Mass (m) = 0.450 Kg
Force (F) = 38 N
Acceleration (a) =?
F = m × a
38 = 0.450 × a
Divide both side by 0.450
a = 38 / 0.450
a = 84.44 m/s²
Finally, we shall determine the distance. This can be obtained as follow:
Initial velocity (u) = 2.20 m/s.
Final velocity (v) = 6 m/s
Acceleration (a) = 84.44 m/s²
Distance (s) =?
v² = u² + 2as
6² = 2.2² + (2 × 84.44 × s)
36 = 4.4 + 168.88s
Collect like terms
36 – 4.84 = 168.88s
31.52 = 168.88s
Divide both side by 168.88
s = 31.52 / 168.88
s = 0.187 m
Thus, the distance is 0.187 m
Answer:
9.9 s
Explanation:
mass (m) = 1000 kg
initial speed (u) = 90 km/h
final speed (v) = 45 km/h
relationship between the speed (v) of the boat and the frictional force (fk) ⇒ fk = 70v
- the acceleration of the system will be given by (a) =
- acceleration is also the first differential of velocity with respect to time,
a =
- therefore acceleration (a) = =
- recall that fk = 70v
(a) = = =
(a) = =
- integrating both side of the equatin we have
t =
- the time required for the boat to slow down = t = = - 9.9 s = 9.9 s