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2 years ago

15

suppose that you want to build a machine to perform simple tasks. why must you understand all about forces to complete your miss

ion?

1 answer:

mixas84 [53]2 years ago

4 0

Answer:

CAUSE YPU WANT TO

Explanation:

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What role do producers play

nikklg [1K]

Answer:

they are the source of energy for primary consumers... they also produce oxygen and sugar

3 0

2 years ago

Read 2 more answers

Y_Kistochka [10]

Answer:

The target was higher than the cannon

Explanation:

Given that a cannon ball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s.

The initial velocity must be 56 m/s, while the final velocity will be 35 m/s.

When an object is thrown upward with an initial velocity, the object continues to move upwards with decreasing in magnitude of velocity till it reaches the maximum height where the final velocity will be equal to zero.

In this question, since the final velocity is less than the initial velocity, we can conclude that the target is higher.

Therefore, the target was higher than the cannon.

5 0

3 years ago

Calculate the applied force to the piston with a 12cm radius required to elevate a weight of 2.0X104N by the piston with a 36cm

Alex

Answer:

Option D is the correct answer.

Explanation:

Refer the figure given.

By Pascal's principle we have

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

F2 = 2 x 10⁴ N

$A_1=\frac{\pi\times (12\times 10^{-3})^2}{4}=1.13\times 10^{-4}m^2\\\\A_2=\frac{\pi\times (36\times 10^{-3})^2}{4}=1.02\times 10^{-3}m^2$

Substituting

$\frac{F_1}{1.13\times 10^{-4}}=\frac{2\times 10^4}{1.02\times 10^{-3}}\\\\F_1=2.22\times 10^3N$

Option D is the correct answer.

6 0

3 years ago

14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?

Vladimir79 [104]

The relationship between resistance R and resistivity $\rho$ is
$R= \frac{\rho L}{A}$
where L is the length of the wire and A its cross section.

The radius of the wire is half the diameter:
$r= \frac{d}{2}= \frac{1.6 mm}{2}=0.8 mm=8\cdot 10^{-4} m$
and the cross section is
$A=\pi r^2 = \pi (8\cdot 10^{-4} m)^2=2.01\cdot 10^{-6} m^2$

From the first equation, we can then find the length of the wire when $R=4.8 \Omega$ (copper resistivity: $\rho = 1.724 \cdot 10^{-8} \Omega m$ )
$L= \frac{AR}{\rho}= \frac{(2.01\cdot 10^{-6} m^2)(1.724 \cdot 10^{-8} \Omega m)}{4.8 \Omega}=7.21 \cdot 10^{-15} m$

4 0

3 years ago

The air molecules around a candle flame are excited by the increased energy and spread out, decreasing in density and rising abo

MAVERICK [17]

The answer is b I believe

3 0

2 years ago