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jok3333 [9.3K]
1 year ago
11

A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance ro

und to the nearest thousand
Physics
1 answer:
Vlada [557]1 year ago
7 0

The strength of the electric field on the point charge at this distance will be 4000 V/m.

<h3>What is the strength of the electric field?</h3>

The strength of the electric field is the ratio of electric force per unit charge.

The given data in the problem is;

Qis the unit charge = 4.0 × 10⁻⁶ C

E is the strength of the electric field

R is the distance from point charge = 3 m

The strength of the electric field is;

\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.

To learn more about the strength of the electric field refer to the link;

brainly.com/question/15170044

#SPJ1

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Answer:

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                                         r is the distance of 0.08 between the charges

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Therefore F_1 = \frac{1.95 \times 10^{-9} \times 3.78 \times 10^{-9}}{4 \times \pi \times 8.854 \time 10^{-12} \times (0.08)^2}    =  10.35 \times 10^{-6} Newton in the positive x direction.

b.) The electrostatic force on the 1.95 nC particle is the same as the electrostatic force on the 3.78 nC particle except that its direction is in the negative x- axis direction.

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v_o=\sqrt{\frac{6.674*10^{-11}\frac{m^3}{kg\cdot s^2}(5.98*10^{24}kg)}{6.37*10^6m}}\\v_o=2503.08\frac{m}{s}

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Therefore,

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