1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jok3333 [9.3K]
1 year ago
11

A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance ro

und to the nearest thousand
Physics
1 answer:
Vlada [557]1 year ago
7 0

The strength of the electric field on the point charge at this distance will be 4000 V/m.

<h3>What is the strength of the electric field?</h3>

The strength of the electric field is the ratio of electric force per unit charge.

The given data in the problem is;

Qis the unit charge = 4.0 × 10⁻⁶ C

E is the strength of the electric field

R is the distance from point charge = 3 m

The strength of the electric field is;

\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.

To learn more about the strength of the electric field refer to the link;

brainly.com/question/15170044

#SPJ1

You might be interested in
A tennis ball has a mass of 0.058 kg and is moving to the right at 40 m/s. What is the momentum
Arte-miy333 [17]

Explanation:

Mass = 0.058Kg

Velocity = 40m/s

Momentum P = ?

P = mv

P = 0.058 × 40

P = 2.32Kgm/s

4 0
3 years ago
A myopic person (assume no astigmatism) is diagnosed with a far point of 160 cm. What corrective prescription should they be sup
Kazeer [188]

Answer:

The person should use a convex lens of power -0.625 D.

Explanation:

Given that, the far point of the person, with myopic eye, is 160 cm.

It means that the image of an object, which is at infinity, is formed at this point 160 cm distance away from the person's eye.

If the object is infinity, then the object distance, u = -\infty.

Image distance, v = -160 cm.

u and v are taken to be negative because the object and the image of the object are on the side of the eye from where the light is coming.

Let the focal length of the lens which is to be used for the correction of this myopic eye be f, then using lens equation,

\rm \dfrac 1f = \dfrac 1v-\dfrac 1u=\dfrac 1{-160 }-\dfrac1{-\infty}=\dfrac 1{-160}-0=\dfrac 1{-160}.\\\Rightarrow f=-160\ cm.

The negative focal length indicates that the lens should be convex.

The power of the lens is given by

\rm P=\dfrac{1}{f}=\dfrac{1}{-160\ cm }=\dfrac{1}{-1.6\ m}=-0.625\ D.

So, the person should use a convex lens of power -0.625 D.

8 0
3 years ago
Read 2 more answers
A 1.0-kg cart and a 0.50-kg cart sit at different positions on a low-friction track. You push on the 1.0-kg cart with a constant
Margarita [4]

Answer:

a)W=0.8J

b) d_t=0.20m

c) \triangle K.E=0.267J

Explanation:

From the question we are told that:

Mass of cart 1 M_1=1.0kg

Mass of cart 1 M_2=0.05kg

Force on  cart 1 F_1=4.0N

Push Distance of cart 1 d_1=0.20m

Slide Distance of cart 1 d_1'=0.35m

a)

Generally the equation for work-done is mathematically given by

W=f*d\\W=4*0.20\\W=0.8J \\

b)

The systems center of mass moved a net totally of (while being pushed)

Mass 1 =0.20m

Mass 2=0

Therefore

d_t=d_1+d_2

d_t=0.20+0

d_t=0.20m

c)

Since work-done is equal to K.E energy of cart 1

Therefore

W=1/2mv^2

V_1=\sqrt{\frac{W}{1/2m}}

V_1=\sqrt{\frac{0.8}{1/2(1)}}

V_1=1.264

Therefore Kinetic energy before collision is

K.E_1=1/2mv^2

K.E_1=1/2*1*1.264^2

K.E_1=0.768

Generally from the equation for conservation  of momentum the Velocity of cart 2 is mathematically given by

v_2=\frac{m_1V_1}{m_1+m_2}

v_2=\frac{1*1.264}{1+0.5}

V_2=0.842m/s

Therefore the final K.E is mathematically given by

K.E_2=(1/2)(m_1+m_2)V_2^2

K.E_2=1/2*(1.5)(0.842)^2

K.E_2=0.531J

Generally the Change in K.E is mathematically given by

\triangle K.E=K.E_1-K.E_2

\triangle K.E=0.798-0.531

\triangle K.E=0.267J

Therefore the will force change the kinetic energy of the system's center of mass by

\triangle K.E=0.267J

4 0
3 years ago
Please help anyone ASAP You can listen to your friend round a corner, but you cannot watch him/her .Why? Related to sound
asambeis [7]

Answer:

The sound waves have larger wavelength than light waves. These are diffracted by the corner of wall and light waves cannot do so, due to their very small wavelength (as compared with size of wall corner). So, without seeing the friends his/her voice can be heard.

6 0
3 years ago
A car moves with an average speed of 45 miles/hour. How long does the car take to travel 90 miles?
Elis [28]

Answer:

B

Explanation:

45+45=90

45 per hour

so, 2 hours

5 0
2 years ago
Read 2 more answers
Other questions:
  • A train travels 85 kilometers in 5 hours, and then 63 kilometers in 5 hours what is its average speed?
    5·1 answer
  • W
    6·1 answer
  • During a tennis serve, a racket is given an angular acceleration of magnitude 150 rad/s^2. At the top of the serve, the racket h
    6·1 answer
  • What horizontal force is required to drag a 15.8 kg block a long a horizontal surface with a coefficient of friction of 0.3, at
    7·1 answer
  • Determine the vertex form of g(x) = x2 + 2x - 1. Which graph represents g(x)?<br> 5) Intro
    9·1 answer
  • What is the acceleration of a baseball that has a final velocity of 15.0 m/s when it crosses the plate 2.0 seconds after leaving
    12·1 answer
  • In a heat engine, if 500 J of heat enters the system, and the piston does 300 J of work.
    12·2 answers
  • 6. An elephant is putting 25,000 newtons of force on Leah. The elephant
    8·1 answer
  • A person with a near point of 85 cm, but excellent distant vision, normally wears corrective glasses. But he loses them while tr
    15·1 answer
  • It takes you 9.8 min to walk with an average velocity of 1.9 m/s to the north from the bus stop to the museum entrance.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!