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umka2103 [35]
2 years ago
15

In order to create a system of equations with the same solution as the system {x+y=102x+y=14, { x+y=10 2x+y=14 , Camilo multipli

ed both sides of the second equation by a number, added the new equation to the first equation, and replaced the first equation with the result. Which system of equations could be Camilo's new system?
Mathematics
1 answer:
Alex777 [14]2 years ago
4 0

Answer:

-3x-y=-18

2x+y=14

Step-by-step explanation

i re took the test until i got it right to answer this lol, its correct and good luck with school

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Please Help me answer all 4 questions with a full explanation so I can solve the rest on my own.
Nata [24]

\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y

\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}

\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}

\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6

6 0
2 years ago
What is the distance between (4,2) and (-1,-3)
Sati [7]
<h2>Solving for the Distance between two Points</h2><h3>Answer:</h3>

5 \sqrt{2} or 7.071

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about distances between two points: <u>brainly.com/question/24629826</u></em>

Given:

(4,2)

(-1,-3)

Solving for the Distance:

\sqrt{(4-(-1))^2 +(2 -(-3))^2} \\ \sqrt{(4 +1)^2 +(2 +3)^2} \\ \sqrt{5^2 +5^2} \\ \sqrt{25 +25} \\ \sqrt{50} \\ \sqrt{25 \cdot 2} \\ 5 \sqrt{2}

<u>Note:</u>

5 \sqrt{2} \approx 7.071

4 0
2 years ago
9 – 4x = 2x whats the ancewer
zmey [24]

Answer:

3/2 is the answer

Step-by-step explanation:

5 0
3 years ago
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kherson [118]

Answer:

-1/3

Step-by-step explanation:

3 is the gradient of the other line

m1×m2=-1 (equation for perpendicular lines)

m1×3= -1

m1= -1/3

Pls confirm if its correct

correct me if wrong

thanks! :)

7 0
2 years ago
What is being done to the variable in the equation y + 8.5 = 17.2?
olganol [36]
<span>The number 8.5 is being added. </span>
3 0
3 years ago
Read 2 more answers
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