Answer:
(A) is your answer. The graph of g(x) will eventually exceed the graph of f(x)
Step-by-step explanation:
The third is because the prove is x = fifteen and if a number is next to a letter, it means multiply, sorry I could only do one.
Answer:
slope: -(9/8)
y-intercept: 7
equation: y = -(9/8)x + 7
Step-by-step explanation:
Solve for the slope.
<em>m</em> (slope) = (y₂ - y₁)/(x₂ - x₁)
Let:
(x₁ , y₁) = (8 , -2)
(x₂ , y₂) = (0 , 7)
Plug in the corresponding numbers to the corresponding variables:
<em>m </em>= (7 - (-2))/(0 - 8)
<em>m</em> = (7 + 2)/(0 - 8)
<em>m</em> = 9/-8
Your slope is -(9/8)
Solve for the y-intercept. Plug in your slope into the slope intercept form:
y = mx + b
Let:
(x , y) = (0 , 7) & m = -(9/8)
Plug in the corresponding numbers to the corresponding variables:
7 = -(9/8)(0) + b
Simplify:
7 = (-9/8 * 0) + b
7 = (0) + b
b = 7
Your y-intercept is 7.
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Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5