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Wittaler [7]
3 years ago
14

Which expression is equivalent to 3/32x8y10

Mathematics
1 answer:
dusya [7]3 years ago
8 0

Answer:

I think #2

Step-by-step explanation:

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The functions f(x) and g(x) are shown below:
Flura [38]

Answer:

(A) is your answer. The graph of g(x) will eventually exceed the graph of f(x)

Step-by-step explanation:

6 0
3 years ago
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Please help me i beg you!!! 30 points!!!
Westkost [7]
The third is because the prove is x = fifteen and if a number is next to a letter, it means multiply, sorry I could only do one.
6 0
3 years ago
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What is the slope? helpppp?
EleoNora [17]

Answer:

slope: -(9/8)

y-intercept: 7

equation: y = -(9/8)x + 7

Step-by-step explanation:

Solve for the slope.

<em>m</em> (slope) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (8 , -2)

(x₂ , y₂) = (0 , 7)

Plug in the corresponding numbers to the corresponding variables:

<em>m </em>= (7 - (-2))/(0 - 8)

<em>m</em> = (7 + 2)/(0 - 8)

<em>m</em> = 9/-8

Your slope is -(9/8)

Solve for the y-intercept. Plug in your slope into the slope intercept form:

y = mx + b

Let:

(x , y) = (0 , 7) & m = -(9/8)

Plug in the corresponding numbers to the corresponding variables:

7 = -(9/8)(0) + b

Simplify:

7 = (-9/8 * 0) + b

7 = (0) + b

b = 7

Your y-intercept is 7.

~

7 0
3 years ago
What is the surface area?<br> 10 ft<br> 8 ft<br> 10 ft<br> 12 ft<br> 10 ft
amid [387]

Answer:

12×8/2=48

10×10=100

2(48)+3(100)

96+300= 396ft²

5 0
2 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
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