Caused by a difference in how one or more of the light-sensitive cells
affects: Difficulty distinguishing between colorsInability to see shades or tones of the same color
1.1 / 2 = .7 --> 2.86 yrs
.7 / 2 = .45 —> 5.72 yrs
.45 / 2 = .225 —> 8.58 yrs
.225 / 2 = .1125 —> 11.44 yrs
So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.
Hope this helps
Answer:
K2CO3 = K2O + CO2
Explanation:
In a chemical equation, the number of atoms on the left needs to be balanced with the number of atoms on the right, and there has to be the same number of the same *type* of atom on both sides as well.
On the left:
2 K
1 C
3 O
and on the right,
2 K
1 O
On the right, there are a few atoms missing, specifically, 1 C and 2 O.
The missing atoms then should be added to the side missing the atoms, preferably in a stable molecule. Luckily, CO2 contains exactly 1 C, and 2 O s, and is quite stable. So, a "CO2" has to be added on the left
Explanation:
Experiment Initial [CS2] (mol/L) Initial Rate (mol/L·s)
1 0.100 2.7 × 10−7
2 0.080 2.2 × 10−7
3 0.055 1.5 × 10−7
4 0.044 1.2 × 10−7
a) Choose the rate law for the decomposition of CS2.
Comparing equations 1 and 3, reducing the initial concentration by almost half (from 0.100 to 0.055) leads too the rate of reaction to be reduced by almost half (from 2.7 × 10−7 to 1.5 × 10−7).
This signifies that the reaction is a first order reaction.
Rate = k [CS2]
(b) Calculate the average value of the rate constant.
Taking equation 1.
Rate = k [CS2]
k = Rate / [CS2]
k = 0.100 / (2.7 × 10−7) = 0.037 x 10^8 = 3.7 x 10^6s-1
Answer:
A standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.
All the data is given in the question and these are as follows:-
Moles - 0.75
Na - 6.022*10^{23
The formula we are using to find the molecules is as follows:-
n = \frac{molecule}{Na}n=
Na
molecule
After, putting the value and solving it. we will get
0.75 * 6.022*10^2^3 = 4.5165*10^{23