3 years ago

I do not have a question anymore

Chemistry

2 answers:

vlabodo [156]3 years ago

6 0

Is this supposed to be for free poi nts??

IrinaK [193]3 years ago

4 0

Answer:

I dont have a answer

Explanation:

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Is this molecule polar or nonpolar?

lutik1710 [3]

The answer is nonpolar

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2 years ago

Where can you find a polar ice biome that contains pack ice and no soil?

ycow [4]

Answer:

APEX answer North Pole

Explanation:

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Mice21 [21]

Answer:

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Explanation:

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3 years ago

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guys please help me WILL MARK BARINLIEST If you have 5.7 x 10^24 molecules of O2 at STP, how many liters of O2 do you have? must

zmey [24]

Answer:

212.8 dm^3 or L

Explanation:

1 mole of any sub=6.02×10^23 molecules

X mole of O2=5.7×10^24 molecules

X mole=5.7×10^24/6.02×10^23

=9.5 mole

1 mole of any gas at stp=22.4 dm^3

Therefore, 9.5 mole of O2 will be 22.4×9.5

=212.8 dm^3

5 0

2 years ago

The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an

ser-zykov [4K]

Answer:

$24540\frac{mg}{m^3}$

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

$\frac{3L\ CO}{L\ gas}$

By using the ideal gas equation we compute the density of CO:

$\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L$

Then we apply the conversion factors as follows:

$=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}$

Regards.

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3 years ago