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Vika [28.1K]
4 years ago
6

Determination of the amount of patassium hydroxide in patassium hydroxide/Sodium carbonate mixture

Chemistry
1 answer:
Eva8 [605]4 years ago
6 0

Answer:

do you still need this answer?

Explanation:

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During the third stage of labor what happens? (it's not C)
QveST [7]

Answer:

B

Explanation:

placenta comes after baby

5 0
2 years ago
What structural features help us identify a compound as an alkane, a cycloalkane, an alkene, an alkyne, a saturated hydrocarbon
elena55 [62]
1. Cycloalkane
2. Alkene
3. Saturated Hydrocarbon
4. Aromatic Hydrocarbon
5. Alkane
6. Alkyne
5 0
3 years ago
A small hole in the wing of a space shuttle requires a 15.9 cm2 patch.
Rzqust [24]

The patch area in square kilometers is 1.59*10⁻⁹ km₂

Why?

This is an unit conversion problem. We have to convert from cm² to km². We can do that by knowing that there are 100 cm in 1 m, and 1000 m in 1 km, so 100000 cm=1km. Knowing that we can apply the following conversion factor:

15.9 cm^{2} * (\frac{1 km}{100000 cm} )^{2}=0.00000000159 km^{2}

Now to convert this value to scientific notation, we have to move the decimal point to the right until we get a whole number, and the exponent of the number 10 is going to be the number of spaces we moved to the right (negative), so the final answer is:

0.00000000159 km^{2}=1.59*10^{-9} km^{2}

Have a nice day!

#LearnwithBrainly

8 0
3 years ago
What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water​
m_a_m_a [10]

Answer:

Molar Mass of Calcium Carbonate = 100g

given mass = 50g

Number of mole of Calcium Carbonate =50/100 = 0.5 mole

Molarity = mole per litre of volume

Molarity = 0.5 /0.25 = 2mole/litre

Explanation:

hope it helps ......

mark me as brainliest ❤️

7 0
3 years ago
Read 2 more answers
Calculate the fraction of acetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You
Sliva [168]

Answer:

0.11%

Explanation:

Without mincing words, let us dive straight into the solution to the question/problem. The first step to solve this question is to write out the chemical reaction, that is the reaction showing the dissociation of acetic acid.

CH3COOH <=======================================> CH3COO⁻ + H⁺

Initially, the amount present in the acetic acid which is = 12M, the concentration for CH3COO⁻  and H⁺ is 0 respectively.

At equilibrium, the amount present in the acetic acid which is = 12 - x, the concentration for CH3COO⁻ = x  and H⁺ = x respectively. Note that the ka for acetic acid = 1.8 × 10⁻⁵.

1.8 × 10⁻⁵ = x²/ 14 - x. Therefore, x = 0.0158 M.

The next thing to do is to calculate for the percentage of dissociation, this can be done as given below:

percentage of dissociation = x/14 × 100. Recall that the value that we got for x = 0.0158 M. Hence, the percentage of dissociation = 0.0158 M/ 14m × 100 = 0.11%

7 0
2 years ago
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