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AysviL [449]
3 years ago
12

Sid lives 3 miles north and 8 miles west of school. What is the direct distance from Sid's house to school?

Mathematics
2 answers:
borishaifa [10]3 years ago
6 0

Answer:the answer yo the question is D

Step-by-step explanation:

OLEGan [10]3 years ago
3 0
A because 3+8=11miles direct
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Drag the measurements to put them in order From least to greatest 7 g 7 kg seven centigrams 7 mg
Arturiano [62]

Answer:

7 mg, 7 centigrams, 7g, 7kg

3 0
3 years ago
james borrows Php 700000 and promises to pay the principal and interest at 15% compounded monthly. How much must he repay after
Licemer1 [7]

Answer:

A = $ 1,987,379.10 + 700,000= $2,687,379.10

Step-by-step explanation:

15% = 0.15 rate per tear

A = P (1+r/n)^nt

A = 700,000 (1+0.015/12)^12*7

A = 700,000 (1+0.0125)^84

A = 700,000 ((0.9875)^84

A = 700,000 (2.839113)

4 0
2 years ago
Philip did 14 setups on Monday 21 sit-ups on Tuesday and 28 sit-ups on Wednesday if the pattern continues how many sit-ups will
g100num [7]
So you add 7 every time so,

28+7=34
34+7=41

if he continues his pattern he will have done 41 sit-ups on Friday
7 0
3 years ago
Sandeep used 8 litres of fuel to travel 76 miles.
OleMash [197]

Answer:

I got, when calculated, 209 miles. (It may be wrong)

Step-by-step explanation:

First, I calculated how many miles can Sandeep travel with 1L, therefore I divided 76 miles by 8L and got 9.5 miles on 1L.

Then I multiplied 9.2 miles by 22L and got 209 miles.

This may be wrong but if anyone else is able to work it out much appreciated if it's correct.. Your most welcome!

4 0
2 years ago
A student ran a distance of 3 miles each day for 5 days. Then the student ran a distance of 4 miles each day for the next 5 days
azamat
The total distance was 35 miles. Why? Well, see below:

The student ran 3 miles each day for 5 days. That can be representative of:

Day 1: 3 miles
Day 2: 3 miles
Day 3: 3 miles
Day 4: 3 miles
Day 5: 3 miles

Adding these values together, we will find that the student ran a total of 15 miles in the first five days.

As for the next set of 5 days, we can represent this by modeling like we did above:

Day 6: 4 miles
Day 7: 4 miles
Day 8: 4 miles
Day 9: 4 miles
Day 10: 4 miles

Adding the values from the second set of days, we will find that in days 6-10, the student ran a total of 20 miles.

We can add the total values together to identify the total distance the student ran during these 10 days.

15 + 20 = 35 total miles

Hence, the student ran a total of 35 miles over the course of 10 days. If you need help, let me know and I will go ally assist you.
8 0
1 year ago
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