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konstantin123 [22]
3 years ago
7

The unit of length most suitable for measuring the thickness of a cell phone is a

Physics
1 answer:
Law Incorporation [45]3 years ago
7 0

The unit of length most suitable for measuring the thickness of a cell phone is millimeter or inches or centimeter.

<u>Explanation: </u>

Cell phones are best used which gets in the size of palms in terms of length and very slim. Mostly the unit of length for the thickness is usually measured in meter scale but as the cell phones tend to slimmer than your palm it generally comes under centimeter scale.

So, it is desirable for the cell phone to be below the centimeter scale. Hence it is specified in terms of centimeter or millimeter. But as technology is enhanced to obtain slimmer smart cell phones, it is most desirable to specify the thickness in terms of millimeters.

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madam [21]

Answer:

stomp???, frictional force

Explanation:

this allow ur foot to be stomp

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2 years ago
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How to find out the heat capacity of a material?​
DochEvi [55]

\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}

The heat capacity is given by the expression:

\longrightarrow \sf{\triangle Q= m \triangle C  \triangle   T}

\longrightarrow \sf{Q= \: Heat}

\longrightarrow \sf{M= \: Mass}

\longrightarrow \sf{C= \: Specific \: Heat}

\longrightarrow \sf{T= \: Temperature}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\leadsto When the \bm{heat} is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in \bm{temperature} , we can then determine the specific heat "C" by simply remplazing in the expression.

5 0
1 year ago
A 10 kg gun recoils with a speed of 0.1 m/s after it fires a 0.001 kg bullet. What is the speed of the bullet?
Kitty [74]

As we know that here gun + bullet system is isolated from all other external force system

so here the momentum of system is always conserved

so we will say

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

v_{1i} = v_{2i} = 0

m_1 = 10 kg

m_2 = 0.001kg

v_{1f} = 0.1 m/s

now we will have

0 + 0 = 10(0.1) + 0.001v_{2f}

by solving above equation we will have

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3 0
3 years ago
A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine
liq [111]

(a) 24.6 Nm

The torque produced by the net thrust about the center of the circle is given by:

\tau = F r

where

F is the magnitude of the thrust

r is the radius of the wire

Here we have

F = 0.795 N

r = 30.9 m

Therefore, the torque produced is

\tau = (0.795 N)(30.9 m)=24.6 N m

(b) 0.035 rad/s^2

The equivalent of Newton's second law for a rotational motion is

\tau = I \alpha

where

\tau is the torque

I is the moment of inertia

\alpha is the angular acceleration

If we consider the airplane as a point mass with mass m = 0.741 kg, then its moment of inertia is

I=mr^2 = (0.741 kg)(30.9 m)^2=707.5 kg m^2

And so we can solve the previous equation to find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{24.6 Nm}{707.5 kg m^2}=0.035 rad/s^2

(c) 1.08 m/s^2

The linear acceleration (tangential acceleration) in a rotational motion is given by

a=\alpha r

where in this problem we have

\alpha = 0.035 rad/s^2 is the angular acceleration

r = 30.9 m is the radius

Substituting the values, we find

a=(0.035 rad/s^2)(30.9 m)=1.08 m/s^2

4 0
3 years ago
When a block slides a certain distance down an incline, the work done by
garik1379 [7]
That is -300 J, because the work = the force times the distance. When the distance is a positive value when it is going down, the distance is a negative value when it is going up. The only thing that change is the minus, the absolute value of the work remains the same
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