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3 years ago

The unit of length most suitable for measuring the thickness of a cell phone is a

Physics

1 answer:

Law Incorporation [45]3 years ago

7 0

The unit of length most suitable for measuring the thickness of a cell phone is millimeter or inches or centimeter.

<u>Explanation: </u>

Cell phones are best used which gets in the size of palms in terms of length and very slim. Mostly the unit of length for the thickness is usually measured in meter scale but as the cell phones tend to slimmer than your palm it generally comes under centimeter scale.

So, it is desirable for the cell phone to be below the centimeter scale. Hence it is specified in terms of centimeter or millimeter. But as technology is enhanced to obtain slimmer smart cell phones, it is most desirable to specify the thickness in terms of millimeters.

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You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,

lbvjy [14]

Answer:

The value is $T_c = 12 .1 ^oC$

Explanation:

From the question we are told that

The mass of the ice cube is $m_i = 7.50 *10^{-3} \ kg$

The temperature of the ice cube is $T_i = 0^o C$

The mass of the copper cube is $m_c = 0.540 \ kg$

The final temperature of both substance is $T_f = 0^oC$

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

$Q = m_c * c_c * [T_c - T_f ]$

The specific heat of copper is $c_c = 385J/kg \cdot ^oC$

Generally the heat gained by the ice cube is mathematically represented as

$Q_1 = m_i * L$

Here L is the latent heat of fusion of the ice with value $L = 3.34 * 10^{5} J/kg$

$Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}$

=> $Q_1 = 2505 \ J$

$2505 = 0.540 * 385 * [T_c - 0 ]$

=> $T_c = 12 .1 ^oC$

4 0

3 years ago

Testosterone is used to treat breast cancer ? True or false?

Triss [41]

Answer:

True

Explanation:

Because I had a test on this

7 0

3 years ago

Calculate the strength and direction of the electric field 300 mm to the right of a -200 C electric

Norma-Jean [14]

Answer: -1.91*10^13 v/m

Explanation:

6 0

3 years ago

Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista

antoniya [11.8K]

The initial velocity of the skier is 4.5 m/s

Explanation:

There is only one force acting on the skier in the horizontal direction, and it is the force of friction, whose magnitude is

$F_f = -\mu_k mg$

where

$\mu_k = 0.050$ is the coefficient of kinetic friction

m is the mass of the skier

$g=9.8 m/s^2$ is the acceleration of gravity

The negative sign is due to the fact that the direction of the force of friction is opposite to the direction of motion of the skier.

According to Newton's second law, the net force acting on the skier is equal to the product between his mass and his acceleration, so we can write:

$F=ma\\ \rightarrow -\mu_k mg = ma$

So, the acceleration of the skier is

$a=-\mu_k g$

Now we can apply the following suvat equation to find the initial velocity of the skier:

$v^2-u^2=2as$

where

v = 0 is the final velocity (he comes to a stop)

u is the initial velocity

s = 21 m is the displacement

a is the acceleration

Substituting the equation for the acceleration and solving for u, we find

$u=\sqrt{v^2-2as}=\sqrt{-2(-\mu_k g) s}=\sqrt{2(0.050)(9.8)(21)}=4.5 m/s$

Learn more about accelerated motion here:

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5 0

3 years ago

If you drop a rock with a density of 1.73 grams will it float or sink

AveGali [126]

Answer:

the rock will sink. this is because it is more dense than water

5 0

3 years ago

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