Answer:
F = 4212 N
Explanation:
Given that,
Mass of a car, m = 1300 kg
Speed of car on the road is 9 m/s
Radius of curve, r = 25 m
We need to find the magnitude of the unbalanced force that steers the car out of its natural straight- line path. The force is called centripetal force. It can be given by :
So, the force has a magnitude of 4212 N
Answer:
Explanation:
Since the pulley has a mass concentrated on its rim, the pulley can be considered as a ring.
The moment of inertia of a ring is
The mass on the left is heavier, that is the pulley is rotating counterclockwise.
By Newton's Second Law, the net torque is equal to moment of inertia times angular acceleration.
Here, the net torque is the sum of the weight on the left and the weight on the right.
Applying Newton's Second Law gives the angular acceleration
The relation between angular acceleration and linear acceleration is
Then, the linear acceleration of the masses is