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babunello [35]
3 years ago
5

Trọng lượng một sp là bnn pp chuẩn với trung bình là 20,5 và độ lệch chuẩn là 2. Lấy ngẫu nhiên 4 sp để kiểm tra thì với xs 0,95

trọng lượng trung bình của chúng sai lệch so với trọng lượng quy định tối đa là bao nhiêu?
Mathematics
1 answer:
Illusion [34]3 years ago
8 0
You need to make this is all languages if you want help thank you . :)
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It’s 12 points thank you
Ket [755]

The value of y when x is equal to zero will be 330.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

The given function is;

y = 330 + 25x

We have to find the value of y when x is equal to zero.

So,

Put x = 0

y = 330 + 25x

y = 330 + 25(0)

y = 330

Hence, the value of y when x is equal to zero will be 330.

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

4 0
2 years ago
What are the zeroes of f(x) = x2 − 2x − 3? (1 point)?
Serjik [45]
We have f(x) = 0;
Then x^2 - 1 - 2x - 2 = 0;
(x - 1)(x + 1) - 2(x + 1) = 0;
(x + 1)(x - 1 - 2) = 0;
(x + 1)(x - 3) = 0;
x + 1 = 0 or x - 3 = 0;
x = -1 or x = 3;
The zeroes of f are -1 and 3.
3 0
3 years ago
Rewrite the following expression X^9/7
KonstantinChe [14]

Answer:

x\sqrt[7]{x^{2} } (D)

Step-by-step explanation:

Given: x^{\frac{9}{7} }

To find: Simplify the given expression

Solution: Simplyfying, we get,

x^{\frac{9}{7} } =x^{\frac{7}{7} +\frac{2}{7}  }

=x^{1} *x^{\frac{2}{7} } \\=x*x^{\frac{2}{7} } \\=x=\sqrt[7]{x^{2} }

Therefore, x\frac{9}{7} can be written as x\sqrt[7]{x^{2} }

5 0
2 years ago
A student finds the slope of the line between (8,7) and (1,4). She writes 17-4/1-8. What mistake did she make
Ksju [112]

Answer:

It's supposed to be 4-7/1-8

Step-by-step explanation:

The formula for slope is y1 - y2 / x1 - x2 (subscript). So you would take the y value from (8,7) which is 7, and subtract by the y value from (1,4), which is 4. You do the same for the x values and you get 7-4/8-1, which is 3/7.

3 0
3 years ago
Solve these:<br> 4x+5=29<br> 2(x-4)=40
Temka [501]
4x + 5 = 29

Subtract 5 on both sides

4x = 24

Divide by 4

X = 6

Now the second one:
2(x-4) = 40

Distribute the 2 into the parenthesis

2x - 8 = 40

Add 8 on both sides

2x = 48

Divide by 2

X = 24


I hope this Helps!
8 0
3 years ago
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