Answer:
A horse ranch offers guests the choice of 8 different horses. They can also choose to ride bareback or with a saddle. Finally, there are 3 different paths to ride on. How many different ways can guests make their selection?
Step-by-step explanation:
sorry if im wrong
The answer is -270 because its closer to 0 than any other numbers
Answer:
C. -8/3
Step-by-step explanation:
3t + 4 = -4
3t = -4 - 4
3t = -8
t = -8/3
C: none of these are solutions to the given equation.
• If<em> y(x)</em> = <em>e</em>², then <em>y</em> is constant and <em>y'</em> = 0. Then <em>y'</em> - <em>y</em> = -<em>e</em>² ≠ 0.
• If <em>y(x)</em> = <em>x</em>, then <em>y'</em> = 1, but <em>y'</em> - <em>y</em> = 1 - <em>x</em> ≠ 0.
The actual solution is easy to find, since this equation is separable.
<em>y'</em> - <em>y</em> = 0
d<em>y</em>/d<em>x</em> = <em>y</em>
d<em>y</em>/<em>y</em> = d<em>x</em>
∫ d<em>y</em>/<em>y</em> = ∫ d<em>x</em>
ln|<em>y</em>| = <em>x</em> + <em>C</em>
<em>y</em> = exp(<em>x</em> + <em>C </em>)
<em>y</em> = <em>C</em> exp(<em>x</em>) = <em>C</em> <em>eˣ</em>
Part A:
From the graph, it seems that the lines intersect at (3,-1)... This seems to be the solution...
Part B:
g(x) is a negative line, and the slope is 2 (from rise/run). Y int. = 5. So, the equation is -2x+5. Plug in some numbers for this; say 1 and 2. The coordinates would be (1,3) and (2,1).
Part C:
The 2 graphs seem to intersect at (0,5), so this is the solution...
ALL of this is based on only looking at the graph, which is no better than drawing lines on the sand.. For example, the y intercept for g(x) could be 4.9 or 5.1, and I don't know the equation for f(x)... Based on the info I have, gave my best answers..
Hope this helps..
