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nadya68 [22]
2 years ago
8

I feel like it would be 6/10 but that’s not an answer

Mathematics
1 answer:
kupik [55]2 years ago
6 0

Answer:

I think it would be 3/4

Step-by-step explanation:

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Marla started her school work at 8:48am. If she has to do 4 hours of school, what time will she be off?
grigory [225]

Answer:

See below.

Step-by-step explanation:

Q) 8:48 a.m. + 4 hours

= <u>12:48 p.m.</u>

<u></u>

Bonus Q) 8:56 a.m. + 4 hours

= <u>12:56 p.m.</u>

<u></u>

<u>They will both be off by 12:56 p.m.</u>

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8 0
2 years ago
Read 2 more answers
Graph the image of the given triangle under a dilation with a scale factor of −2 and center of dilation (0, 0) .
Ronch [10]

To dilate an object means to enlarge or reduce the size of the object. The scale factor will determine how much larger or smaller the object will become.  If this factor is greater than 1, the object will increase in size. Otherwise, if the factor is less than 1, the object will decrease in size. So, the dilated object will be similar to its original. On the other hand, when corresponding points of the original and dilated figures are connected by straight lines, the center of dilation is the point where all the lines meet. In this problem, the center is (0, 0). When the center is the origin we need to multiply all the original coordinates of the object by the scale factor given. So:


A(-4, 1) \rightarrow A'=-2(-4,1) \rightarrow A'(8,-2) \\ \\ B(-3, -4) \rightarrow B'=-2(-3,-4) \rightarrow B'(6,8) \\ \\ C(-2, -2) \rightarrow C'=-2(-2,-2) \rightarrow C'(4,4)


So, the graph of the dilated triangle is shown in the Figure below

8 0
3 years ago
Read 2 more answers
The gradiant y=2x³-5x+1 at point (2,7)​
olga2289 [7]

Given:

The equation of the curve is:

y=2x^3-5x+1

To find:

The gradient (slope) of the given curve at point (2,7).

Solution:

We have,

y=2x^3-5x+1

Differentiate the given equation with respect to x.

y=2(3x^2)-5(1)+(0)

y'=6x^2-5

Now we need to find the value of this derivative at (2,7).

y'_{(2,7)}=6(2)^2-5

y'_{(2,7)}=6(4)-5

y'_{(2,7)}=24-5

y'_{(2,7)}=19

Therefore, the gradient (slope) of the given curve at point (2,7) is 19.

8 0
2 years ago
What are the coordinates of the vertices of the figure A'B'C'after the following transformation. (x,y) ---&gt; ( y, -x)​
topjm [15]

9514 1404 393

Answer:

  • A'(4, 4)
  • B'(4, 2)
  • C'(1, 2)

Step-by-step explanation:

Using the transformation ...

  (x,y) ⇒ (y, -x) . . . . . . rotation 90° CW

we have ...

  A(-4, 4) ⇒ A'(4, 4)

  B(-2, 4) ⇒ B'(4, 2)

  C( -2, 1) ⇒ C'(1, 2)

5 0
2 years ago
How does the graph of g(x) = -(x + 3)4 compare to the parent function of f(x) = xº?
AnnyKZ [126]

Answer:

g(x) is shifted 3 units to the left and reflected over the x-axis.

Step-by-step explanation:

8 0
3 years ago
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