C.
Matter can not be created or destroyed, so in a closed system it stays constant
10.0 gram sample of H20(l) at 23.0°C absorbs. 209 joules of heat. What is the final temperature of H20(l) sample?
The answer is A hopes that helps
2al(8)+6HCI(aq)->3H2(g)+2AICI3(aq)
this reaction is between a metal and an acid which typically results in a salt and the release of hydrogen gas.
Answer:
Empirical formula = C₃S₂
Explanation:
Given data:
Mass of carbon = 44.0 mg (44/1000 = 0.044 g)
Mass of sulfur = 122 mg - 44.0 mg = 78 mg = 78/1000 = 0.078 g)
Empirical formula = ?
Solution:
First of all we will calculate the number of moles.
Number of moles of carbon = mass / molar mass
Number of moles of carbon = 0.044 g/ 12.01 g/mol
Number of moles of carbon = 0.0037 mol
Number of moles of sulfur:
Number of moles = mass / molar mass
Number of moles = 0.078 g/ 32,066 g/mol
Number of moles = 0.0024 mol
Now we will compare the moles:
C : S
0.0037/0.0024 : 0.0024/0.0024
1.5 : 1
C : S = 2(1.5 : 1)
C : S = 3 : 2
Empirical formula = C₃S₂
