Answer:
months
Step-by-step explanation:
Given that company 
charges 
upfront and 
per month and company B does not charge the upfront fee but charges 
per month.
Let after 
months both the company charges the same amount.
Total charges by the company 
and total charges by the company 
.
Now, from the given condition both the charges are equal, so
Hence, after months both the company charges the same amount.
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
all real numbers.
Step-by-step explanation:
First, distribute 3 to all terms within the parenthesis:
3(x + 4) = 3(x) + 3(4) = 3x + 12
3x + 12 = 3x + 12
Because both sides are the same, your answer for x is "all real numbers".
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It is A hope this helps :)
