How much energy is required to completely melt a 250 gram ice cube that is already at 0 degrees Celsius? Show your work & un
its. Expected Answer = 83,500 J
1 answer:
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Answer:
- <em><u>Option B) All the ammonia is consumed</u></em>
Explanation:
<u>1. Balanced chemical equation (given):</u>
<u>2. Theoretical mole ratios:</u>
<u>3. Limiting reactant:</u>
When 1 mole of ammonia is combined with 2 moles of oxygen, the mole ratio is:
Hence, one of the reactants will be completely consumed (the limiting reactant) and, after completion, an excess of the other will remain unreacted.
You need to compare the the actual ratio with the theoretical ratio.
- 4/5 > 1/2
Hence, NH₃ is in less proportion with respect to oxygen than what is theoretically needed, and the former is the limiting reactant.
Therefore, the 1 mole (all) of ammonia will be consumed, while some oxygen will remain as excess. This is described by the option B) All the ammonia is consumed.
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<u>4. Analyze the other options:</u>
The amount of oxygen that will react is:
And the amount that will remain is:
Neither option A) nor C) describe that situation.
The amount of water produced is:
, which is not described by the option D).
Hence, the correct answer is the option B) All the ammonia is consumed.
The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:
PV = k
where k is a constant.
We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,
P₁V₁ = P₂V₂
Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.
In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa. Substituting these values in the previous equation and clearing V₂, we have,
P₁V₁ = P₂V₂ → V₂ =
→ V₂ =
→ V₂ = 75 mL
Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL