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3 years ago

Marco went to the cafeteria to buy chicken sandwiches, C, worth $2.00, and hamburgers, h, worth $2.50.

Mathematics

2 answers:

yaroslaw [1]3 years ago

6 0

Answer:

5 Hamburgers = $12.50 4 Chicken sandwiches $8.00( $12.50 + $8.00 = $20.50

Step-by-step explanation:

soldi70 [24.7K]3 years ago

5 0

Answer:

Marco bought 5 hamburgers and 4 chicken sandwiches.

Step-by-step explanation:

Set up a system of equations:

2c + 2.5h = 20.5

c + h = 9

Solve by elimination by multiplying the bottom equation by -2:

2c + 2.5h = 20.5

-2c - 2h = -18

Add the equations together and solve for h:

0.5h = 2.5

h = 5

So, he bought 5 hamburgers. Plug in 5 as h into the second equation to solve for c:

c + h = 9

c + 5 = 9

c = 4

So, Marco bought 5 hamburgers and 4 chicken sandwiches.

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ana wants to earn 88 percent in her chemistry class she has one quiz left to take on the first 5 quizzes she received a 74 perce

Alinara [238K]

Answer: 91

Step-by-step explanation: I assume you had a typo and mean what did Ana need on the 5th quiz since you only listed 4 quiz scores.

(74 + 92 + 83 + 100 + x)/5 = 88

(349 + x)/5 = 88

((349 +x)/5) x 5 = 88 x 5

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3 years ago

What step do u preform first when evaluating the expression 3 + (18 - 6) + 20 divided by 4

Elena L [17]

Answer:

Step-by-step explanation:

=3+(18-6)+20÷4

=3+12+20÷4

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=20

use BODMAS rule (Bracket of Division, Multiplication, Addition, and Subtraction)

5 0

2 years ago

Read 2 more answers

Honda Atlas issued 100,000 shares of stock. In 1990, each share of stock was worth Rs. 152.50. In 1993, each share of the stock

noname [10]

Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

No. of stocks issued in 1990 = 100,000

Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990 = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

No. of stocks 1993 = 100,000

Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993 = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

= Rs. 15,250,000 - Rs. 2,120,000

= Rs.13,130 ,000

Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

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3 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago

Please help!!! ill mark brainliest

Vesnalui [34]

3x - 1 = 3x + 1

subtract 3x from both sides to get (-1 = 1). This is a false statement so it is: CONTRADICTION

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4x - 11 = 7

add 11 to both sides and then divide both sides by 4 to get $(x = \frac{18}{4} = \frac{9}{2})$ . This statement is true only when x = $\frac{9}{2}$ so it is: CONDITIONAL

*************************************************

2 - 8x = 2 - 8x

add 8x to both sides to get (2 = 2). This is a true statement so it is: IDENTITY

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x + 1 = -x + 4

add x to both sides, subtract 1 from both sides, and divide both sides by 2 to get $(x = \frac{3}{2} )$ . This statement is true only when x = $\frac{3}{2}$ so it is: CONDITIONAL

Answer: B, A, C, A

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3 years ago