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slava [35]
4 years ago
7

What must a food handler use to determine the concentration of sanitizing solution?

Chemistry
2 answers:
Marina86 [1]4 years ago
8 0

Answer:

He must test the solution with a sanitizer kit.

Explanation:

The concentration of sanitizing solution must be tested with a sanitizing kit. It is composed of disinfectant test strips that measure the sanitizing solution concentration. A very important part of the daily operation of a food establishment is the proper disinfection of the equipment.  Generally, chlorine is used to disinfect multipurpose utensils, food contact surfaces and other food preparation items. Over time, the concentration of chlorine decreases due to volatile elements.

Have a nice day!

sattari [20]4 years ago
3 0
I believe a food handler must use a test kit to determine the concentration of sanitizing solution. Sanitizing reduces pathogens on a surface to safe levels. The sanitizer are the agents that are used for sanitizing ; their effectiveness is determined by the factors such as concentration, contact time, pH, temperature, and also water hardness.
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A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
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Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

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