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slava [35]
3 years ago
7

What must a food handler use to determine the concentration of sanitizing solution?

Chemistry
2 answers:
Marina86 [1]3 years ago
8 0

Answer:

He must test the solution with a sanitizer kit.

Explanation:

The concentration of sanitizing solution must be tested with a sanitizing kit. It is composed of disinfectant test strips that measure the sanitizing solution concentration. A very important part of the daily operation of a food establishment is the proper disinfection of the equipment.  Generally, chlorine is used to disinfect multipurpose utensils, food contact surfaces and other food preparation items. Over time, the concentration of chlorine decreases due to volatile elements.

Have a nice day!

sattari [20]3 years ago
3 0
I believe a food handler must use a test kit to determine the concentration of sanitizing solution. Sanitizing reduces pathogens on a surface to safe levels. The sanitizer are the agents that are used for sanitizing ; their effectiveness is determined by the factors such as concentration, contact time, pH, temperature, and also water hardness.
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Classify each reaction and write to formula of each product or products: (image attached)
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Explanation:

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4 years ago
6. Many changes have been made to atomic theory since Daltons time.
skelet666 [1.2K]

Answer:

A. Modern atomic theory is, of course, a little more involved than Dalton's theory but the essence of Dalton's theory remains valid. ... Also, there are different kinds of atoms (differing by their masses) within an element that are known as "isotopes", but isotopes of an element have the same chemical properties.

B. The explanation becomes a scientific theory. In everyday language a theory means a hunch or speculation. Not so in science. In science, the word theory refers to a comprehensive explanation of an important feature of nature supported by facts gathered over time.

8 0
4 years ago
Is the normal resting position of an object.
NemiM [27]

Answer:

being stationary relative to a particular frame of reference or another object; when the position of a body with respect to its surroundings does not change with time it is said to be at rest

Explanation:

4 0
3 years ago
2A1 + 3Cl2 → 2AICI:<br> a) How many moles of AICIz form when 3.2 mol of Cl2 reacts?
crimeas [40]

Answer:

<u>2.13</u> moles of AlCl3 are produced from 3.2 moles of Cl2

Explanation:

Moles : The amount of substance that contain as many particles as present in 12 grams of C-12.

The balanced equation for the reaction is :

2Al +3Cl_{2}\rightarrow 2AlCl_{3}

This reaction shows the following :

2 mole Al = 3 mole Cl2 = 2 mole AlCl3

In question we are asked to calculate the moles of AlCl3 produced from Cl2

So, we will use only Cl2 andAlCl3 moles

3 mole Cl2 = 2 mole AlCl3

1 moles of Cl2 will give =

\frac{2}{3} of AlCl3

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\frac{2}{3}\times 3.2 of AlCl3

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7 0
3 years ago
Determine the concentration of nh3(aq) that is required to dissolve 743 mg of agcl(s) in 100.0 ml of solution. the ksp of agcl i
AnnyKZ [126]

Answer:

1.1 M

Explanation:

The dissociation of AgCl_{(s)} is as follows:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Given Value for K_{sp} = 1.77*10^{-10}

The equation for the reaction for the formation of complex ion Ag(NH_3)^+_2 is :

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

The value of K_f = 1.6*10^7

If we combine both equation and find the overall equilibrium constant will be:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

<u>                                                                                                      </u>

AgCl_{(s)}+2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

                                 K = (1.77*10^{-10})(1.6*10^7)

                                  K = 0.00283

If [NH_3] = x M

The solubility of  AgCl_{(s)} in the NH_3 solution will be:

x = 743*10^{-3}g * \frac{mol AgCl}{143.32g}*\frac{1}{0.1000L}

x = 0.0518 M

Constructing an ICE Table; we have :

                             AgCl_{(s)} + 2 NH_3{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

Initial  (M)                                     x                   0                      0

Change  (M)                       -2 (0.0518)      + 0.0518          + 0.0518

Equilibrium (M)                    x - 0.1156          0.0518             0.0518

Equilibrium constant;

(K) = \frac{[Ag(NH_3)_2^+][Cl^-]}{[NH_3]^2}

0.00283 = \frac{(0.0518)^2}{(x-0.1156)^2}

0.00283 = (\frac{0.0518}{x-0.1156})^2

x = 0.1156 + \sqrt{\frac{0.0518^2}{0.00283} }

x = [NH₃] =  1.089 M

[NH₃] ≅ 1.1 M                

8 0
3 years ago
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