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sweet-ann [11.9K]
3 years ago
8

If liquid water is exposed to normal atmospheric pressure, what needs to change in order to change its state of matter?

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
5 0
Mass of water because then it will change his States of matter
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___1___Zn + __2___HCl → ___1___H2 + ____1__ZnCl2
strojnjashka [21]

Answer:

Mass = 2.8 g

Explanation:

Given data:

Mass of HCl = 102 g

Mass of Zn = 128 g

Mass of H₂ = ?

Solution:

Chemical equation:

2HCl + Zn      →     H₂ + ZnCl₂

Number of moles of Zn:

Number of moles = mass/molar mass

Number of moles = 128 g/ 65.38 g/mol

Number of moles = 2 mol

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 102 g/ 36.5 g/mol

Number of moles = 2.8  mol

Now we will compare the moles of hydrogen gas with HCl and Zn.

                   HCl          :        H₂

                     2            :        1

                     2.8         :       1/2×2.8 = 1.4 mol

                   Zn          :        H₂

                     1            :        1

                     2           :         2

Number of moles of hydrogen formed by HCl are less thus it will limiting reactant.

Mass of Hydrogen:

Mass = number of moles × molar mass

Mass = 1.4 mol ×  2 g/mol

Mass = 2.8 g

7 0
3 years ago
Calculate the atomic mass of copper if copper-63 is 69.17% abundant and copper-65 is 30% abundant
astraxan [27]

Answer:List of isotopes

Nuclide Z Isotopic mass (Da)

Excitation energy

63Cu 29 62.9295975(6)

64Cu 29 63.9297642(6)

65Cu 29 64.9277895(7)

Explanation:

6 0
3 years ago
Any DBZ fans??????????????????????//<br><br> ??????????????
Mnenie [13.5K]

Answer:

ummmmmmmmmm what's that???

8 0
3 years ago
Read 2 more answers
An opening volumetric cylinder filled with water at volume 0.003m after period of
raketka [301]

Answer:

= - 303.975 Joules

Explanation:

Given that:

The volume of the cylinder = 0.003 m^3

Now, to liters:

The volume = 0.003 *1000 L

= 3 L

For an open cylinder, we mean the atmospheric pressure is at standard condition.

Thus, the workdone = -PΔV

= - 1 atm (3 L)

= - 3 L atm

1 L atm to Joules

= 101.325 Joules

Therefore;

=- 3* 101.325 Joules

= - 303.975 Joules

7 0
4 years ago
In the oxidation of iron; how many grams of iron (III) oxide will be produced from 6.20 mol of Fe?
Flura [38]

Answer:

496 g of Fe₂O₃.

Explanation:

The balanced equation for the reaction is given below:

4Fe + 3O₂ —> 2Fe₂O₃

From the balanced equation above,

4 moles of Fe reacted to produce 2 moles of Fe₂O₃.

Therefore, 6.20 moles of Fe will react to produce = (6.20 × 2)/4 = 3.1 moles of Fe₂O₃

Finally, we shall determine the mass of 3.1 moles of Fe₂O₃. This can be obtained as follow:

Mole of Fe₂O₃ = 3.1 moles

Molar mass of Fe₂O₃ = (56 × 2) + (3×16)

= 112 + 48

= 160 g/mol

Mass of Fe₂O₃ =?

Mass = mole × molar mass

Mass of Fe₂O₃ = 3.1 × 160

Mass of Fe₂O₃ = 496 g

Therefore, 496 g of Fe₂O₃ were produced from the reaction.

8 0
3 years ago
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