A compound is more stable in the combined form.
The answer is "c" because solidification or freezing is the term used for the process in which a liquid becomes a solid.<span> Freezing is an exothermic process that also is an example of a phase transition</span>
Answer:
Explanation:
Molarity of NaOAc needed
Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.
pH = pKa + log [NaOAc]/[HOAc]
5.00 = 4.75 + log[NaOAc]/[1.00M]
5.00 - 4.75 = log [NaOAc] - log[1.00M]
log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78
Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.
Determine Volume of Base Needed
(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base
Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.
Checking Results:
5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00 QED.
Mass of lead Pb = 4.00 g (given)
Density of lead= 11.34 g/mL (given)
When lead is placed in a graduated cylinder which is partially filled with water, the volume of lead will be the volume of water displaced by it.
Density (d) of a substance is the ratio of mass (m) to the volume (m) of the substance.
The formula of density is given as:
![d= \frac{m}{v}](https://tex.z-dn.net/?f=d%3D%20%5Cfrac%7Bm%7D%7Bv%7D)
Putting the given values of density and mass of lead, we get
![11.34 g/mL= \frac{4.00 g}{v}](https://tex.z-dn.net/?f=11.34%20g%2FmL%3D%20%5Cfrac%7B4.00%20g%7D%7Bv%7D)
Rearrange the equation, to find the volume
![V= \frac{4.00 g}{11.34 g/mL}](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B4.00%20g%7D%7B11.34%20g%2FmL%7D)
![V= 0.3527 mL \simeq 0.353 mL](https://tex.z-dn.net/?f=V%3D%200.3527%20mL%20%5Csimeq%200.353%20mL)
Therefore, volume replaced by lead is 0.353 mL