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tatuchka [14]
3 years ago
14

*Absurd answers will be reported* Can the fraction 12/30 be reduced/simplified? If it can, what can it be reduced by?

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Si se puede 12/30 se simplifica por 2 y pasa a 6/15 luego se simplifica por 3 y pasa a 2/5 y ya no se puede más

Fynjy0 [20]3 years ago
4 0

Answer:

divided by 3 12/30 = 4/10 = 2/5

Step-by-step explanation:

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3 years ago
The difference of two complementary angles is 48. Find the measures of the two angles.
Furkat [3]

The larger angle is 55 deg at the larger angle.

We have to know which angles are called Complementary Angles...

if we add two angles and the total will be equal to 90 deg

let's say one angle is x and  another angle is  y

as they are complementary angles from the definition we can write the equation x + y =  90

one angle is 20 deg more  than another one  so from the above condition  we write x = 20 + y

Substitute the value of x  in the first eaquation we get, 20 + y + y =  90

Then,  20 + 2y =  90

subtracting 20 from both sides,

 2y  =  90-20 = 70  

 dividing both sides by 2,

2y/ 2 = 70 / 2

 y  =  35

 So we got one angle is 35 deg

another angle is  35 + 20 = 55 deg.

Our answer is 55 deg the larger angle.

To learn more about the measure angle visit:

brainly.com/question/25716982

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3 0
2 years ago
a 16 inch wire is to be cut. one piece is to be bent into the shape of a​ square, whereas the other piece is to be bent into the
Lyrx [107]
1. Let x be a length of square side, then the square perimeter is 4x (you need to cut 4x from 16 in. to make a square with side x in.). Then 16-4x is remained length of wire and you have to make form this piece a rectangle with sides one of which is twice bigger than another. If y is length of the smaller side, then 2y is length of the bigger side and rectangle perimeter is y+2y+y+2y=6y. You have 16-4x in. of wire left, so 6y=16-4x and y= \frac{16-4x}{6}.

2.
 A_{square}=x^2 \\ A_{rectangle}=y\cdot 2y=\frac{16-4x}{6}\cdot2\cdot\frac{16-4x}{6}= \frac{(16-4x)^2}{18}  \\ A(x)=A_{square}+A_{rectangle}=x^2+\frac{(16-4x)^2}{18}.

3. Find the derivative of the function A(x): 
A'(x)=2x+ \dfrac{2(16-4x)\cdot(-4)}{18} =2x- \dfrac{4(16-4x )}{9}.

4. Solve the equation A'(x)=0: 
2x- \dfrac{4(16-4x )}{9}=0 \\ 18x-64+16x=0 \\ 34x=64 \\ x= \frac{32}{17}

5. Since y= \frac{16-4x}{6} you have

y= \dfrac{16-4 \frac{32}{17} }{6} = \dfrac{16\cdot17-4\cdot32}{6\cdot 17} = \dfrac{24}{17}.

Answer: <span>the width of the rectangle is \frac{24}{17}</span>




6 0
3 years ago
I am<br> thinking of a #at least 13
steposvetlana [31]

Answer:

what do u mean

skjfjdkd

3 0
3 years ago
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