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tatuchka [14]
3 years ago
14

*Absurd answers will be reported* Can the fraction 12/30 be reduced/simplified? If it can, what can it be reduced by?

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Si se puede 12/30 se simplifica por 2 y pasa a 6/15 luego se simplifica por 3 y pasa a 2/5 y ya no se puede más

Fynjy0 [20]3 years ago
4 0

Answer:

divided by 3 12/30 = 4/10 = 2/5

Step-by-step explanation:

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Can someone please help me with this
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180 = 96 + 3x + 12

180 = 108 + 3x

-108  -108

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2 years ago
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9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of
netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 12, \sigma = 3

What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

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Z = 1.33

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9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

5 0
2 years ago
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Answer:

C

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All you need to do p(x)-q(x).  So:

(x^{2}-1)-(5)(x-1)

That's it!


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3 years ago
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