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Usimov [2.4K]
3 years ago
5

What expression is equivalent to x2 - 49

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

Answer:

x^2 - 49= (x+7) (x -7)

Step-by-step explanation:

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A cake is shaped like a cylinder with a diameter of 9 in. The height of the cake is 6 in.
miv72 [106K]

Answer: 121.5 pi in^3 or 381.7 in^3

Step-by-step explanation:

Volume of a cylinder = pi r^2(h)

Radius = 4.5 in, Height = 6 in

pi (4.5)^2(6)

pi(20.25)(6)

121.5 pi in^3 or 381.7 in^3

6 0
3 years ago
Read 2 more answers
Hi I need help in this question
dalvyx [7]

Answer:

First part representing requirements for the length x>=5 ft

Second part yes

Step-by-step explanation:

Well, the formula for finding the area of a rectangle is l x w. In the question, it states that the pen must be 4 ft wide and to fit his requirements of the pen being at the minimum 20 ft^2 we have this inequality 4x>=20 which we must solve and we get x>=5 which means that this represents all of the possible lengths for the play space. For the second part, we know that to fufill Judah's requirements for square ft., our length must be greater than or equal to 5. Last time I was doing math, I'm pretty sure 5 1/2>5 which thus can be accepted as a length value, still meeting the requirements of at least 20ft^2 space for the play space.

7 0
3 years ago
How to simplify 1/2/1/8
kramer
Frist you simplify the mixed number: We have a 4/8. To simplify, we will use the common factor 4. Divide the numerator and denominator by 4 and you will get 1/2.
8 0
3 years ago
Wright 69 over 8 as a mixed number
shusha [124]

Answer:

8 5/8

Step-by-step explanation:

hope this helps!

:)

6 0
3 years ago
Read 2 more answers
I need the solution
Nataly [62]

The only thing you can do here is to try to simplify, so I'll assume that's what you want to do.

\dfrac{b^2-a^2}{2a^2+ab-3b^2}

The numerator is a difference of squares, so it's easy to factorize:

b^2-a^2=(b-a)(b+a)

In the denominator, we factorize by grouping:

2a^2+ab-3b^2=2a^2-2ab+3ab-3b^2=2a(a-b)+3b(a-b)=(2a+3b)(a-b)

So we have

\dfrac{b^2-a^2}{2a^2+ab-3b^2}=\dfrac{(b-a)(b+a)}{(2a+3b)(a-b)}=-\dfrac{b+a}{2a+3b}

5 0
4 years ago
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