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3 years ago

If the imaginary element Blobbium (Bb) formed an acid with the formula H₃Bb, what should this acid be named? *

Chemistry

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

Explanation:

The non metal in HCl is Chlorine and the name of the acid is Hydrochloric acid.

H = hydro

Cl = chloric

So I imagine this new acid, yet to be discovered even by the crew of the Star Ship enterprise, would be

HydroBlobbic acid

I await news from Spock on how things are going on the discovery of such a thing. So far he has not said anything about it.

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When solving an equation using Gay-Lussac's law, which of the following steps do not apply? A. List your knowns and unknowns. B.

suter [353]

Answer:

C. Plug the unknowns into the ideal gas law formula.

Explanation:

Gay-Lussac's law states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as:

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where

p1 is the initial pressure

T1 is the initial temperature (in Kelvin)

p2 is the final pressure

T2 is the final temperature (in Kelvin)

Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:

A. List your knowns and unknowns.

B. Convert temperature to kelvin.

D. Solve for the unknown.

While the following step is not needed:

C. Plug the unknowns into the ideal gas law formula.

Because we do not need to use the ideal gas law formula.

8 0

3 years ago

Water can be formed in the following reaction:

andreev551 [17]

Answer is: 10 moles of water will be produced.

Balanced chemical reaction of formation of water:

2H₂ + O₂ → 2H₂O.

n(H₂) = 10 mol; amount of hydrogen gas.

From balanced chemical reaction: n(H₂) : n(H₂O) = 2 : 2 (1 : 1).

n(H₂O) = n(H₂).

n(H₂O) = 10 mol; amount of water.

6 0

3 years ago

You have a 15.0 gram sample of gold at 20.0°C. How much heat does it take to raise the temperature to 100.0°C?

Nadusha1986 [10]

Answer:

=154.8 J

Explanation:

The rise in temperature is contributed by the change in temperature.

Change in enthalpy = MC∅, where M is the mass of the substance, C is the specific heat capacity and ∅ is the change in temperature.

Change in temperature = 100.0°C-20.0°C=80°C

ΔH=MC∅

The specific heat capacity of gold= 0.129 J/g°C

ΔH= 15.0g×0.129J/g°C×80°C

=154.8 J

7 0

3 years ago

How is hydrogen in heavy water different from hydrogen in normal water?

tatyana61 [14]

Answer:

I'd say the correct answer is A

Explanation:

hope this helps:)

sorry if its wrong:(

6 0

2 years ago

PLEEASE HELP TIMED WILL GIVE BRAINLIEST TO CORRECT ANSWER NLY PLEASEEEE HELPPPP

Arturiano [62]

Answer:

1) 1.15 mol

2) M=0.45

3) 22.5 mL

4) 6.25 mL

Explanation:

550 mL= 0.55 L

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (2.1 M * 0.55 L ) M=1.15 mol solute

155 mL = 0.155 L

80 g -> 1 mol NH4NO3

5.61 g -> x

x= (5.61 g * 1 mol NH4NO3)/80 g x= 0.07 mol NH4NO3

M=(0.07 mol NH4NO3)/0.155 L M=0.45

3) M1V1=M2V2

V1= M2V2/M1

V1= (0.500 M * 0.225 L)/5.00 M V1=0.0225 L =22.5 mL

4) M1V1=M2V2

V1= M2V2/M1

V1= (0.25 M * 0.45 L)/ 18.0 M

V1=6.25 x 10^-3 L = 6.25 mL

8 0

2 years ago

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