Complete this worksheet. I DARE YOU!!! if you have the will power to

Attractive forces of liquids allow for _____.

kap26 [50]

Answer:

They allow particles to stay close together.

The attractive forces (bonds) in a liquid are strong enough to keep the particles close together, but weak enough to let them move around each other. For example, Liquids are useful in car brake systems because they flow and cannot be compressed.

Explanation:

Hope this helps :)

3 0

3 years ago

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Write the complete balanced equation for the following reaction: c7h14 o2 yields co2 h2o

Svetach [21]

C7H14 + 10.5 O2 -> 7 CO2 + 7 H2O

Or, if whole numbers must be used:

2 C7H14 + 21 O2 -> 14 CO2 + 7 H2O

3 0

3 years ago

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Which too factors determine whether a collision between two reactant molecules will result in a reaction? select all that apply.

stepan [7]

Answer:

The particles must be in the correct orientation upon impact.

The particles must collide with enough energy to meet the activation energy of the reaction.

Explanation:

This a problem related to chemical kinetics. The collision theory is one of the theories of reaction rates and it perfectly explains how the effectiveness of colliding molecules dictates the pace of a reaction.

For reactions to occur, there must be collisions between reacting particles. It implies that the collision per unit time and how successful collisions are determines the rate of chemical reactions in most cases. Therefore, for a collision to be successful, colliding particle must have enough energy which is greater than the activation energy of the reaction. In order to also produce the desired products, the colliding particles must be properly oriented.

8 0

3 years ago

2. Answer the following questions about a sample of calcium phosphate:

weqwewe [10]

Answer:

a) 310.18 g/mol

b) 4.352 moles Ca3(PO4)2

c) 2.6 * 10^24 molecules

d) 5.24 * 10^24 P atoms

e)13.056 moles Ca

f)10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0 = 310.18 g/mol

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = 4.352 moles

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = 2.6 *10^24 molecules

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P = 5.24 * 10^24 P atoms

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = 13.056 moles Ca

Step 8: Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

4 0

3 years ago

What is the molarity of an intravenous glucose solution prepared from 108 g of glucose in 2.0 L of solution? 0.018 mol/L 0.30 mo

scZoUnD [109]

Answer:

0.30 mol/L

Explanation:

Mass = 108 g

Molar mass of glucose = 180.156 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{108\ g}{180.156\ g/mol}$

$Moles= 0.5995\ mol$

Given Volume = 2 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.5995}{2}$

Molarity = 0.3 mol/L

7 0

3 years ago