Question

The molar solubility of cui is 2. 26 × 10-6 m in pure water. Calculate the ksp for cui.

Answer 1

Ksp(the solubility product constant) = [Cu⁺] [I⁻]

So, the Ksp for Cui would be:

Ksp = (2.26 × 10⁻⁶) (2.26 × 10⁻⁶) = 5.11 x 10⁻¹²

Formula used:

K = $K_{sp} = [A^+]^a [B^-]^b$, where

Ksp = solubility product constant

A⁺    = cation in an aquious solution

B⁻ = anion in an aqueous solution

a, b = relative concentrations of a and b

Definition

The equilibrium constant for a solid material dissolving in an aqueous solution is the SOLUBILITY PRODUCT CONSTANT, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.

Take into account the general dissolving response (in aqueous solutions) below:

                           aA(s)⇔cC(aq)+dD(aq)

The molarities or concentrations of the products (cC and dD) must be multiplied in order to find the Ksp. Any product that has a coefficient in front of it must be raised to the power of that coefficient (and also multiply the concentration by that coefficient).

Learn more about the concept of Ksp through the link:

brainly.com/question/1419865

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