The structure of 1-methoxypropane is CH₃-CH₂-CH₂-OCH₃
I will label the carbons A-D from left to right.
A B C D
CH₃-CH₂-CH₂-OCH₃
In a proton NMR spectrum, we are looking at the chemical shifts of each unique hydrogen atom, and the splitting patterns tell us how many hydrogens are attached to the adjacent carbon. Therefore, the signal from the protons on carbon A will be split by the protons on carbon B, and the signal for protons on carbon A will have a splitting pattern equal to n+1, where n = number of hydrogens on the adjacent carbon.
Therefore, for the protons on carbon A, there are two neighbouring protons and these will give a splitting patter of 3 peaks, also known as a triplet.
Protons on carbon A: 2 adjacent protons result in a triplet signal.
Protons on carbon B: 5 adjacent protons result in a sextet signal.
Protons on carbon C: 2 adjacent protons result in a triplet signal.
Protons on carbon D: 0 adjacent protons result in a singlet signal.
Answer:- Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%
Solution:- For the percentage composition of a compound, the atomic mass of each atoms times its subscript is divided by the molar mass of the compound and multiplied by 100.
The given compound is 
.
mass of Na = 22.99 g
mass of H = 1.008 g
mass of C = 12.01 g
mass of O = 3(16) = 48 g
Molar mass of compound = 22.99 g + 1.008 g + 12.01 g + 48 g = 84.008 g
percentage of Na = 
= 27.37%
percentage of H = 
= 1.20%
percentage of C = 
= 14.30%
percentage of O = 
= 57.14%
Answer:
Concentration of H3O⁺ [H3O⁺] = 0.864 M
Explanation:
Given that:
The mass concentration of MO = 43 g/L
The volume of MO = 7.9 mL = 7.9 × 10⁻³ L
Recall that
The mass number of MO = Mass concentration of MO × Volume of MO
The mass number of MO = (43 g/L) * (7.9 × 10⁻³ L)
The mass number of MO = 0.3397 g
number of moles of MO = (mass number of MO) / (molar mass of MO)
number of moles of MO = (0.3397 g) / (327.33 g/mol)
moles of MO = 0.00104 mol
The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL
The total volume = 19.95 mL = 19.95 × 10⁻³ L
Concentration of MO [MO} =(number of moles of MO) / (total volume)
[MO] = 0.00104 mol / 19.95 × 10⁻³ L
[MO] = 5.2130 × 10⁻⁸ M
the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution
the number of moles of H3O⁺ = [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]
the number of moles of H3O⁺ = 17.24 mmol
Concentration of H3O⁺ [H3O⁺] = (the number of moles of H3O⁺) / (total volume)
Concentration of H3O⁺ [H3O⁺] = (17.24 mmol) / (19.95 mL)
Concentration of H3O⁺ [H3O⁺] = 0.864 M
The sulphate solutions came from a recycling LIBs waste cathode materials, which were done by previous research; their content is shown in Table 1 [18]. Sodium carbonate (Na2CO3) was purchased from Nihon Shiyaku Reagent, Tokyo, Japan (NaCO3, 99.8%), for the chemical precipitation. CO2 was purchased from Air Product and Chemical, Taipei, Taiwan (CO2 ≥ 99%), to carry out the hydrogenation–decomposition method. Dowex G26 was obtained from Sigma-Aldrich (St. Louis, MO, USA) and was used as a strong acidic cation exchange resin, to remove impurities. Multi-elements ICP standard solutions were acquired from AccuStandard, New Haven, Connecticut State, USA. The nitric acid (HNO3) and sulfuric acid (H2SO4) were acquired from Sigma-Aldrich (St. Louis, MO, USA) (HNO3 ≥ 65%) (H2SO4 ≥ 98%) The materials were analyzed by energy-dispersive X-ray spectroscopy (EDS; XFlash6110, Bruker, Billerica, MA, USA), X-ray diffraction (XRD; DX-2700, Dangdong City, Liaoning, China), scanning electron microscopy (SEM; S-3000N, Hitachi, Tokyo, Japan), and inductively coupled plasma optical emission spectrometry (ICP-OES; Varian, Vista-MPX, PerkinElmer, Waltham, MA, USA). In order to
Appl. Sci. 2018, 8, 2252 3 of 10
control the hydrogenation temperature and heating rate, a thermostatic bath (XMtd-204;
<span>polyunsaturated!!! Hope this helps mark this the brainliest!</span>
