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stellarik [79]
3 years ago
10

In the reaction 2K + 2H2O→2KOH + H2 , which compound has an element ratio of 2:1 ?

Chemistry
2 answers:
Katyanochek1 [597]3 years ago
5 0

Answer:

Option O = H₂O

Explanation:

Chemical reaction:

2K + 2H₂O   →     2KOH + H₂

In this balanced chemical equation we can see that water is the only compound that consist of two hydrogen atom and one oxygen atom. H : O

2 : 1 .

In case of KOH two hydroxyl and two potassium atom are present and ration is K:OH  1:1.

stich3 [128]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

A compound is defined as the substance in which different elements are chemically combine together in a fixed ratio by mass.

For example, H_{2}O and KOH are both compounds in the given reaction equation.

Here, in H_{2}O the atoms are present in 2:1 ratio and in KOH compound the atoms are present in 1:1 ratio.

A compound can be divided into its constituent or simpler substances.

Thus, we can conclude that in the given reaction only H_{2}O is the compound which has an element ratio of 2:1.

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Two moles of an ideal gas are placed in a container whose volume is 2.3 x 10^-3 m3. The absolute pressure of the gas is 6.9 x 10
PtichkaEL [24]

Answer:

K.E.=1.97\times 10^{-21}\ J

Explanation:

Given that:-

Pressure = 6.9\times 10^5\ Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = \frac {1}{101325} P (atm)

Given the value of pressure = 43,836 Pa

So,  

6.9\times 10^5\ Pa = \frac{6.9\times 10^5}{101325} atm

Pressure = 6.80977 atm

Volume = 2.3\times 10^{-3}\ m^3 = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

K.E.=\frac{3}{2}\times K\times T

k is Boltzmann's constant = 1.38\times 10^{-23}\ J/K

T is the temperature

So, K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J

K.E.=1.97\times 10^{-21}\ J

3 0
3 years ago
Given that 7.25 moles of carbon monoxide gas are present in a container of volume 11.90 L, what is the pressure of the gas (in a
d1i1m1o1n [39]

Answer:17.955atm

Explanation:Pv=nrt

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P= 214.1505/11.90

P=17.995atm

6 0
3 years ago
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