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tekilochka [14]
2 years ago
6

What is the hydrogen ion concentration in molarity if the hydroxide ion concentration is 7.609 10-13 ?

Chemistry
1 answer:
mihalych1998 [28]2 years ago
3 0

Answer: The hydrogen ion concentration in molarity is 0.013

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pOH is calculated by taking negative logarithm of hydroxide ion concentration and pH is calculated by taking negative logarithm of hydrogen ion concentration

 

Putting in the values:

pOH=-\log[7.609\times 10^{-13}]

pOH=12.1

Now , pH+pOH=14

pH=14-12.1=1.9

pH=-\log [H^+]

[H^+]=0.013M

The hydrogen ion concentration in molarity is 0.013

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The mass fractions of a mixture of gases are 15 percent nitrogen, 5 percent helium, 60 percent methane, and 20 percent ethane wi
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Answer:

Explanation:

mass fraction N₂ : He : CH₄ : C₂H₆ : : 15 : 5 : 60 : 20

mole fraction  N₂ : He : CH₄ : C₂H₆ : : 15/28 : 5/4 : 60/16 : 20/30

mole fraction  N₂ : He : CH₄ : C₂H₆ : : .5357  : 1.25 : 3.75 : .67

Total mole fractions = .5357 + 1.25 + 3.75 + 0.67 = 6.2057

mole fraction of N₂ =  .5357 / 6.2057 = .0877

mole fraction of He = 1.25 / 6.2057 = .20

mole fraction of CH₄ = 3.75 / 6.2057 = .6043

mole fraction of C₂H₆ = .67 / 6.2057 = .108

Partial pressure = total pressure x mole fraction

Partial pressure of N₂ = 1200 kPa  x .0877 = 105.24 kPa

Partial pressure of He = 1200 kPa  x .20  = 240 kPa

Partial pressure of CH₄ = 1200 kPa  x  .6043  = 725.16 kPa

Partial pressure of C₂H₆ = 1200 kPa  x .108    = 129.6 kPa

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3 years ago
How much heat is released when you condense 93.9 g of water vapor? <br><br> Show work please ❤️
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<u>Answer:</u>

211.9 J

<u>Explanation:</u>

The molecules of water release heat during the transition of water vapor to liquid water, but the temperature of the water does not change with it.

The amount of heat released can be represented by the formula:

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The latent heat of evaporation for water is L=2257 kJ/kg and the mass of the water is m=93.9 g=0.0939 kg.

The amount of heat released in this process is:

Q=mL_e = (0.0939kg)(2257 kJ/kg)= 211.9 J

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