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Mazyrski [523]
3 years ago
12

How many atoms of lead are contained in 0.532mol?​

Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

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Read 2 more answers
I need help with these last two questions, thanks!
Vitek1552 [10]
Both of these questions can be solved using the equation M1V1 = M2V2, where M is concentration anf V is volume.

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