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Mazyrski [523]
3 years ago
12

How many atoms of lead are contained in 0.532mol?​

Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

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Arlecino [84]

Answer:

the answer is c

Explanation:

7 0
3 years ago
Which ionic compound is the most likely to dissolve in water?
lbvjy [14]
The ionic compound is CaSO4
3 0
3 years ago
2 HCl + Na2SO4 > 2 NaCl + H2SO4
Cerrena [4.2K]

Answer:

15

Explanation:

8 0
2 years ago
1: At which temperature would a reaction withΔH = -102 kJ/mol, ΔS = -0.188 kJ/(mol×K) be spontaneous? 2: At which temperature wo
Naddik [55]

Answer:

1: At temperatures below 542.55 K

2: At temperatures above 660 K

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

\Delta G=\Delta H-T\Delta S

Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

1:

0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.

2:

0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K

It means that at temperatures higher than 660 K the reaction will be spontaneous.

Best regards!

7 0
2 years ago
Calculate the number of moles of caco3 (calcium carbonate, or limestone) in a 20.0g sample of this substance
Brrunno [24]
First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.

     molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃

Then, divide the given amount of substance by the calculated molar mass.
            number of moles = (20 g)(1 mol of CaCO₃/100 g)
             number of moles = 0.2 moles of CaCO₃

<em>Answer: 0.2 moles</em>
6 0
3 years ago
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