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bagirrra123 [75]
3 years ago
7

How many secondary (2°) carbons are found in 5-ethyl-3,3,4-trimethylheptane??

Chemistry
2 answers:
Gelneren [198K]3 years ago
6 0
5-Ethyl-3,3,4-trimethylheptane has 3 secondary carbon. A primary carbon written as 1° is a carbon that has one carbon atom attached to it. A secondary carbon written as 2° is a carbon attached to two other carbons, while a tertiary carbon written as 3° is a carbon attached to three other carbons. 
Kipish [7]3 years ago
3 0

Answer:

3 secondary carbons are found in 5-ethyl-3,3,4-trimethylheptane.

Explanation:

5-ethyl-3,3,4-trimethylheptane's structure can be seen in the attached picture, in this structure, each vertex represents one carbon atom.

<em>A secondary carbon</em> is a carbon that is bonded to only 2 other carbon atoms, each secondary carbon is highlighted in blue in the attached picture.

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Answer: 1.027 x 10^6 g= 1027kg
In this question, you are given the volume of the blimp (2.027×10^5 ft^3) and the density of the gas(0.179g/L). To answer this question, you need to convert the volume unit into liter. The calculation would be: 2.027×10^5 ft^3 x 28.3168L/ft3= 57.398 x 10^5L= 5.74x10^6L

Then to find the mass, multiply the volume with the density. The calculation would be: 5.74x10^6L x 0.179g/L= 1.027 x 10^6 g= 1027kg
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3 years ago
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How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
miss Akunina [59]
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
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M1 = 2M
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</span>plug in the givens in the above equation:
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</span>therefore:
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Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

7 0
3 years ago
A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05
Sedbober [7]

The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
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  • Molarity = 0.3 M
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Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
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  • Mole of Na₂SO₄ = 0.075 mole
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Mass = mole × molar mass

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Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.

Learn more about molarity:

brainly.com/question/15370276

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2 years ago
A sample of helium gas occupies a volume of 152.0 mL at a pressure of 717.0 mm Hg and a temperature of 315.0 K. What will the vo
kozerog [31]

Answer:

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V1 = 0.152 L (I was taught to always convert milliliters to liters)

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