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3 years ago

Which of the following are always larger than the neutral atoms from which they are formed?

Chemistry

1 answer:

Anuta_ua [19.1K]3 years ago

3 0

Answer:

A) Cations

Explanation:

a) Cations have a positive charge and are larger than their neutral counterparts!

b) Anions have a negative charge and are smaller than their neutral counterparts

c) Metals can have either a positive or negative charge making it either a cation or an anion

d) Carbon is an element and it can have a charge anywhere from +4 to -4

A good way to remember that cations are positive is to think that CATions are always PAWSitive! ^-^

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If element A is in Group 13 and element B is in Group 17, which ions will be formed when A and B react together?

Kobotan [32]

Answer:

A3+ and B-

Explanation:

Elements in group 13 have outermost electron configuration, ns2np1 hence they form trivalent positive ions.

Elements in group 17 have outermost electron configuration ns2np5 hence they form univalent negative ions.

This implies that, if element A is in Group 13 and element B is in Group 17, the ions formed are A3+ and B-.

8 0

2 years ago

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only __________ can be easily oxidized becau

tatiyna

Answer:

Aldehydes
A hydrogen atom
Oxygen

Explanation:

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only aldehydes can be easily oxidized because there is a hydrogen atom next to the carbonyl and oxidation does not require oxygen

4 0

3 years ago

Select the single best answer. Which mechanism properly shows the movement of electrons in the reaction? 2xsafari

sweet [91]

Answer:

Explanation:

We must study the reaction pictured in the question closely before we begin to attempt to answer the question.

Now, the reaction is a free radical reaction. This implies that only one electron is transferred. The transfer of one electron is shown using a half arrow rather than a full arrow. The both species are radicals (odd electron species) and contribute one electron each.

Hence we must show electron movements in both species using a half arrow.

5 0

3 years ago

Ionic or covalent C2H5OH

Afina-wow [57]

Answer:

Covalent

Explanation:

A molecule of C₂H₅OH has C-C, C-H, C-O, and O-H bonds.

A bond between A and B will be ionic if the difference between their electronegativities (ΔEN) is greater than 1.6.

$\begin{array}{ccc}\textbf{Bond} & \textbf{$\Delta$EN} & \textbf{Polarity}\\\text{C-C} & 2.55 - 2.55 = 0.00 & \text{Nonpolar covalent}\\\text{C-H} & 2.55 - 2.20 = 0.35 & \text{Nonpolar covalent}\\\text{C-O} & 3.44 - 2.55 = 0.89 & \text{Polar covalent}\\\text{O-H} & 3.44 - 2.20 = 1.24 & \text{Polar covalent}\\\end{array}$

No bond has a large enough ΔEN to be ionic.

C₂H₅OH is a covalent molecule.

6 0

3 years ago

He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o

Xelga [282]

Answer : The activation energy of the reaction is, $17.285\times 10^4kJ/mole$

Solution :

The relation between the rate constant the activation energy is,

$\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = initial rate constant = $4.55\times 10^{-5}L/mole\text{ s}$

$K_2$ = final rate constant = $8.75\times 10^{-3}L/mole\text{ s}$

$T_1$ = initial temperature = $195^oC=273+195=468K$

$T_2$ = final temperature = $258^oC=273+258=531K$

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

$\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]$

$Ea=17.285\times 10^4kJ/mole$

Therefore, the activation energy of the reaction is, $17.285\times 10^4kJ/mole$

8 0

3 years ago

Read 2 more answers