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3 years ago

10

Solve

1 answer:

liraira [26]3 years ago

7 0

Answer:

y - 3 = (1/2)(x - 4)

Step-by-step explanation:

The graph is hard to read, but we can make assumptions about the x- and y-values shown. The y-intercept appears to be (0, 1) and the blue dot appears to be (4, 3). Let's try finding the equation of the line using this assumed data:

The point-slope equation is y - k = m(x - h), where (h, k) is a point on the line and m is the slope of the line.

We need the slope of the line. Recall that m = rise/run. Going from (0, 1) to (4, 3), x (the 'run') increases by 4 and y (the 'rise') increases by 2. Thus, the slope is m = rise/run = 2/4, or 1/2.

Substituting the known values into the point-slope equation y - k = m(x - h), we get:

y - 3 = (1/2)(x - 4)

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7nadin3 [17]

Answer:

6

Step-by-step explanation:

cancel out 5 by multiplying its by 5, what you do to one side you do to the other. so you also multiply 12 by 5. and you should get 60

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3 years ago

Mrs. Metheney had some donuts. She bought 8 more, and now has 18 in total. Write the equation using d as your variable

Tpy6a [65]

Answer:

y=10d+8

Step-by-step explanation:

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3 years ago

Read 2 more answers

What's the mean of 3 4 5 3 4 5 6 7 1 2 3 4 5 6 4 8 4 3 2 <br> A. 4.1<br> B.4.2<br> C.8.0<br> D.8.3

Bess [88]

Answer:

A. 4.1

Step-by-step explanation:

3+4+ 5+ 3+ 4+ 5+ 6+ 7+ 1+ 2+ 3+ 4+ 5+ 6+ 4+ 8+ 4+ 3+ 2= 79

79/ 19 = 4.1

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3 years ago

Select the description that is true to the equation x + y =2<br><br>

lutik1710 [3]

Number one is correct

7 0

3 years ago

What is the area of the given figure?

kirza4 [7]

$\huge\boxed{192\ \text{in}^2}$

There are three parts to this figure: a rectangle and two triangles that are congruent.

We'll add together the area for each to get the total area.

We'll start by finding the area of the rectangle. We don't know its length, so we need to find the bases of the triangles and add them together.

We know that $a^2+b^2=c^2$ . Substitute and solve for $a$ :

$\begin{aligned}a^2+6^2&=10^2\\a^2+36&=100\\a^2+36-36&=100-36\\a^2&=64\\\sqrt{a^2}&=\sqrt{64}\\a&=8\end{aligned}$

Now, double this to get the total length of the rectangle, which is $16$ inches.

The area of the rectangle is equal to its length times its height:

$16\cdot9=\underline{144}$

Now, we'll find the area of one of the triangles and double it since they're congruent.

The area of a triangle is one-half of its base times its height, which we then double.

$2\left(\frac{1}{2}\cdot b\cdot h\right)$

The $2$ and the $\frac{1}{2}$ cancel each other out.

$b\cdot h$

Substitute and solve:

$8\cdot6=\underline{48}$

Finally, add the rectangle's area to the two triangles' area.

$144+48=\boxed{192}$

6 0

2 years ago