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alexgriva [62]
3 years ago
7

What is the approximate difference in the circumference of a circle with a radius of 4 ft and the circumference of a circle with

a radius of 6 ft?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer: 12.57 ft

Step-by-step explanation:

Circumference of circle with radius of 4ft.

= π * radius * 2

= 22/7 * 4 * 2

= 25.14 ft

Circumference of circle with radius of 6ft.

= 22/7 * 6 * 2

= 37.71 ft

Difference = 37.71 - 25.14

= 12.57 ft

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Well the answer is No.A remainder will always be smaller than the divisor ,because the divisor is the one that used to divide the dividend and the remaining number that cannot be divided by the divisor is called the remainder.
Questions?
6 0
3 years ago
Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly
kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0
3 years ago
Find the number that is 2/3 of the way from 3/4 to 3 5/12
IRINA_888 [86]

Answer:

I got 2.527. And the 7 repeats I’m wasn’t sure if you wanted it in a fraction but it shouldn’t be difficult to convert if you have a calculator with that function

Step-by-step explanation:

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3 years ago
Slove for y . 3x+2y=-6
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Answer:

y = -(6+3x)/2

Step-by-step explanation:

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8 0
3 years ago
A cereal box has dimensions of 1012 inches by 712 inches by 212
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The answer is 196.875 in3

<span>Assuming you meant the following measures

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The volume is V = L*W*H = 10.5 in * 7.5 in *2.5 in = 196.875 in3</span>
3 0
3 years ago
Read 2 more answers
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