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alexgriva [62]
3 years ago
7

What is the approximate difference in the circumference of a circle with a radius of 4 ft and the circumference of a circle with

a radius of 6 ft?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer: 12.57 ft

Step-by-step explanation:

Circumference of circle with radius of 4ft.

= π * radius * 2

= 22/7 * 4 * 2

= 25.14 ft

Circumference of circle with radius of 6ft.

= 22/7 * 6 * 2

= 37.71 ft

Difference = 37.71 - 25.14

= 12.57 ft

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polet [3.4K]

Answer:

qazsxdcfg

Step-by-step explanation:

7 0
2 years ago
Solve for the x in the inequality 6(2−6x)≤4−35x 6 ( 2 − 6 x ) ≤ 4 − 35 x .
dolphi86 [110]

Answer:

8 ≤ x

Step-by-step explanation:

6(2 − 6x) ≤ 4 − 35x

Expand bracket;

12 - 36x ≤ 4 − 35x

Add 36x to both sides to get;

12 ≤ 4 + x

Subtract 4 from both sides to get;

8 ≤ x

5 0
2 years ago
Read 2 more answers
For Joe's illness, the doctor gave him a prescription of 28 pills. He needs to take 4 pills the first day, and then 2 pills each
kiruha [24]

Answer:

12 days.

Step-by-step explanation:

I looked at it this way:

He has to take 4/28 pills the first day, so it's 28-4=24. Then I divided 24 by 2.

In simpler terms:

28-4=24

24/2

12

8 0
3 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
In Jack's class, 7 out of 25 students have hazel eyes. What percent of the class has hazel eyes?
denis23 [38]
You're going to set up a proportion. % over 100 = is over of. You're looking for the percent so that's your x. X over 100=7 over 25. Cross multiply to get 25x=700. Divide both sides by 25 and your answer is 28%
4 0
3 years ago
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