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Monica [59]
3 years ago
7

Hello i need help please

Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0
Option B is correct
elena-s [515]3 years ago
5 0
I think the answer is option b on the graph
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Which inequality is equivalent to |x-4|<9
Lorico [155]

Answer with explanation:

The Given Inequality is

  |x-4|<9

Modulus of a number yields always a positive value.

→|x-4|= x-4, when, x-4≥0

                     That is , x≥4.

         = -(x-4), when, x-4<0

                    means, x<4.

     it can be Written as

 → -9<x-4<9

→ -9+4 < x -4+4 < 9+4

→ -5<x<13

→x∈(-5,13)

8 0
3 years ago
Read 2 more answers
Find the cordinates of point A.
Mashutka [201]

Answer:

A=(1,4) B=(-3,4) C=(-3,-1)

Step-by-step explanation: Point B will be plotted in the top left box. You start at 0 and go to your left 3 boxes then you go up one box.

3 0
2 years ago
3, 12, 48, 192, 768, . . .
Sav [38]
The answer would be the sequence has a common ratio of 4.
The explanation for this would be:
To get the common ratio for get the simplest form of the two numbers, so 12/3 = 4 and 48/12 = 4So we know that their common ratio is 4.
To check:
3 x 4 = 12
12 x 4 = 48
48 x 4 = 192
192 x 4 = 768
7 0
3 years ago
Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p
Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t  

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t  = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0
3 years ago
Look at the photo and answer the question.
Tanya [424]

Answer:

second option

Step-by-step explanation:

5 newton pushing it to the right

while a mere 4 newton pushing it to the left

more force pushing towards right

4 0
2 years ago
Read 2 more answers
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