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Firlakuza [10]
2 years ago
12

A recipe uses 4 cups of milk to make 12 servings. If the same amount of milk is used for each serving, how many servings can be

made from three gallons? Before you try that problem, answer the question below. How many cups will you need to find the number of servings for?
Mathematics
1 answer:
Vika [28.1K]2 years ago
5 0

Answer:

144 servings

Step-by-step explanation:

Step 1

We convert 3 gallons to cups

1 gallon = 16 cups

3 gallons = x cups

x = 3 × 16 cups

x = 48 cups

Step 2

If

4 cups of milk = 12 servings.

48 cups of milk = x servings

Cross Multiply

4 × x = 48 × 12

x = 48 × 12/4

x = 144 servings

Therefore, 3 gallons of milk(48 cups) = 144 servings

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My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
Use the vertical line test to determine if the relation {(–6, –2), (–2, 6), (0, 3), (3, 5)} is a function
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Answer: Its a function

Step-by-step explanation:

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Jennifer and Julio each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same sto
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The answer is $9, $5
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5. Marie buys 2 pounds of turkey and 1 pounds of ham. She pays a total of $20,
NARA [144]

Answer:Let t = cost per pound of turkey

Let h = cost per pound of ham

 

4t + 2h = 30

t = h - 1.5

 

substitute h-1.5 in place of t in 1st equation

 

4(h-1.5) + 2h = 30

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6h - 6 = 30

6h = 36

h = 6

 

t = h-1.5 = 4.5

 

1 pound of turkey costs $4.50

1 pound of ham costs    $6.00

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cost of 1 pound each  $10.50

Step-by-step explanation:

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Answer:

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