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Firlakuza [10]
3 years ago
12

A recipe uses 4 cups of milk to make 12 servings. If the same amount of milk is used for each serving, how many servings can be

made from three gallons? Before you try that problem, answer the question below. How many cups will you need to find the number of servings for?
Mathematics
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

144 servings

Step-by-step explanation:

Step 1

We convert 3 gallons to cups

1 gallon = 16 cups

3 gallons = x cups

x = 3 × 16 cups

x = 48 cups

Step 2

If

4 cups of milk = 12 servings.

48 cups of milk = x servings

Cross Multiply

4 × x = 48 × 12

x = 48 × 12/4

x = 144 servings

Therefore, 3 gallons of milk(48 cups) = 144 servings

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drek231 [11]
Isolate x.
24x = 48 - 2y

Divide by 24.
x = 2 - y/12
3 0
3 years ago
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For what values of K does x2+kx+9=0
Airida [17]

Answer:

k = 6

Step-by-step explanation:

x {}^{2}  + kx + 9 = 0

here,

a = 1,

b = k

c = 9

now,

D = b {}^{2}  - 4ac

k {}^{2}  - 4(1)(9) = 0 \\   k {}^{2}  - 36 = 0 \\ k {}^{2}  = 36 \\ k = 6

4 0
3 years ago
Angle Sum Theorem. y = ?
salantis [7]

Answer:

90°

Step-by-step explanation:

Interior angles of ALL triangles sum to 180°

The whole large triangle has angles 60 60 60   ( they sum to 180)

that means x = 30

then the small triangle on the right has     60 + 30 + y = 180

  meaning y = 90 °

8 0
1 year ago
35 POINTS AVAILABLE
aliina [53]

Answer:

Part 1) The length of each side of square AQUA is 3.54\ cm

Part 2) The area of the shaded region is (486\pi-648)\ units^{2}

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

A=\pi r^{2}

we have

A=25\pi\ cm^{2}

substitute in the formula and solve for r

25\pi=\pi r^{2}

simplify

25=r^{2}

r=5\ cm

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

SU=r=5\ cm

Let

x------> the length side of the square

Applying the Pythagoras Theorem

5^{2}=x^{2} +x^{2}

5^{2}=2x^{2}

x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

A=\pi r^{2}    

we have

r=AB=18\ units

substitute in the formula

A=\pi (18)^{2}=324\pi\ units^{2}

step 2

Find the length of each side of square BCDE

we have that

AB=18\ units

The diagonal DB is equal to

DB=(2)18=36\ units

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

36^{2}=x^{2} +x^{2}

1,296=2x^{2}

648=x^{2}

x=\sqrt{648}\ units

step 3

Find the area of the square BCDE

The area of the square is

A=(\sqrt{648})^{2}=648\ units^{2}

step 4

Find the area of the smaller circle

The area of the circle is equal to

A=\pi r^{2}    

we have

r=(\sqrt{648})/2\ units

substitute in the formula

A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}  

step 5

Find the area of the shaded region

324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}

7 0
3 years ago
What is the answer to m^7 · m^−3?
elena55 [62]

Answer:

M^4

Step-by-step explanation:

Here use product law which state- same base power should add

M^7-3

M^4

8 0
3 years ago
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