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Natasha_Volkova [10]
3 years ago
9

Which two statements are true about redox reactions?

Physics
2 answers:
maw [93]3 years ago
8 0

Answer:

A) They are single-replacement reactions.

C) Electrons are both gained and lost.

Explanation:

A.P.E.X

yuradex [85]3 years ago
4 0

Answer:

C. Electrons are both gained and lost

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A horizontal force of magnitude 356 N is employed to push a 78.0-kg block a distance of 18.6 m on a rough horizontal surface. If
icang [17]

Answer:

6621.6 Joule

0.46525

Explanation:

F = Force = 356 N

s = Displacement = 18.6 m

m = Mass of block = 78 kg

Work done

W=F\times s\\\Rightarrow W=356\times 18.6\\\Rightarrow W=6621.6\ J

The work done by the horizontal force is 6621.6 Joule

F=\mu mg\\\Rightarrow \mu=\frac{F}{mg}\\\Rightarrow \mu=\frac{356}{78\times 9.81}\\\Rightarrow \mu=0.46525

The coefficient of friction between the block and the rough surface is 0.46525

5 0
3 years ago
PLEASEEEE HELP MEEEEE!!!!
Reika [66]

Answer:

D. Yes

m

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3 0
3 years ago
In a previous problem, you calculated how much energy was needed to accelerate a 2,100-kg Tesla Model S from 0 to 100 km/hr, and
Naddika [18.5K]

Answer:

t=2.348s

Explanation:

First we need to calculate the Potential Energy of a Tesla to reach the 100km/h

So we know that,

W=KE_f - KE_i = \frac{1}{2}m(V_f^2-V_i^2)=\frac{1}{2}(2100)(27.78^2)W=8.1*10^5J

Here we can to calculate the time through,

t=\frac{W}{P}

t=\frac{8.1*10^5}{345*10^3}

t=2.348s

5 0
3 years ago
If anyone help this question I getting wrong answer. I don’t know why I keep getting wrong. Could anyone help me please?! Please
pishuonlain [190]
Slope formula : y2 - y1 / x2 - x1 

The coordinates are ( 66 , 39)  and ( 12 , 83)

 
                        83 - 39 /  12 - 66 

                            44 / - 54 

                  slope = - 0 . 81 or - 22/27

                        
5 0
3 years ago
The
Finger [1]

Answer:

1.) 10.61 A

2.) 0.27 A

Explanation:

Given that a sinusoidal A.C has a maximum value of 15A.

1) What are its r.m.s values?

ii) If the time is recorded from the instant the current is zero and is becoming

positive, what is the instantaneous value of the current after 1/300s, given the

frequency is 50 Hz.​

Solution.

1.)

The r.m.s current = peak current/root 2

The r.m.s current = 0.7071 × 15

The r.m.s current = 10.61 A

2.)

Given that

Time = 1/300 s

Frequency = 50 Hz

Instantaneous current can be calculated by using the formula

I = I sin wt

Where w = 2πf

Instantaneous current = 15( sin 2πft)

I = 15 × sin ( 2 × 3.143 × 50 × 1/300 )

I = 15 × sin ( 1.047 )

I = 15 × 0.01827

I = 0.27 A

Therefore, the instantaneous current is 0.27A

3 0
3 years ago
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