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Basile [38]
3 years ago
5

Keeping in mind the kinetic energy of a moving vehicle, how can a driver best prepare to enter sharp curves in the roadway?

Physics
1 answer:
4vir4ik [10]3 years ago
4 0
Make your mind get use to slowing down before you reach places like that
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C = speed of light = 3.00 × 108 m/s
Alinara [238K]

The wavelength of the radio broadcast wave given the data is 3.10 m (Option B)

What is wavelength?

ThisThis is simply defined as the distance between two successive crests or trough

Relationships between frequency, wavelength and velocity

The velocity, frequency and wavelength of a wave are related according to the following equation

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

How to determine the wavelength

Velocity (v) = 3×10⁸ m/s

Frequency (f) = 9.67×10⁷ s⁻¹

Wavelength (λ) =?

λ = v /f

λ = 3×10⁸ / 9.67×10⁷

λ = 3.10 m

Learn more about wave:

brainly.com/question/14630790

#SPJ1

3 0
2 years ago
Determine the distance above Earth's surface to a satellite that completes four orbits per day.
serg [7]

This question involves the concepts of the time period, orbital radius, and gravitational constant.  

The distance of the satellite above the Earth's Surface is "10400 km ".

The theoretical time period of the satellite around the earth can be found using the following formula:

\frac{T^2}{R^3}=\frac{4\pi^2}{GM}\\\\

where,

T = Time Period of Satellite = \frac{1}{frequency} = \frac{1}{4\ orbits/day}\frac{3600*24\ s}{1\ day} = 21600\ s

R = Orbital Radius = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of Earth = 5.97 x 10²⁴ kg

Therefore,

\frac{(21600\ s)^2}{R^3}=\frac{4\pi^2}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}\\\\R = \sqrt[3]{\frac{4.66\ x\ 10^8\ s^2}{9.91\ x\ 10^{-14}\ s^2/m^3}} \\R = 1.675\ x\ 10^7\ m = 1.68\ x\ 10^4\ km

Now, this orbital radius is the sum of the radius of the earth (r) and the distance of satellite above earth's (h) surface:

R = r + h

1.68 x 10⁴ km = 0.64 x 10⁴ km + h

h = 1.68 x 10⁴ km - 0.64 x 10⁴ km

<u>h = 1.04 x 10⁴ km = 10400 km</u>

Learn more about the orbital time period here:

brainly.com/question/14494804?referrer=searchResults

The attached picture shows the derivation of the formula for orbital speed.

8 0
3 years ago
An airplane in level flight travels horizontally with a constant eastward acceleration of 8.50 m/s2 and a constant northward acc
zloy xaker [14]

Answer:

d = 3574.3 m

Explanation:

Given that acceleration of the airplane is

a_x = 8.50 m/s^2

a_y = -28 m/s^2

initial velocity is given as

v_x = 83.5 m/s

v_y = -15.5 m/s

now we have displacement in x direction given as

x = v_x t + \frac{1}{2}a_x t^2

x = (83.5)(14) + \frac{1}{2}(8.5)(14)^2

x = 2002 m

Displacement along y direction is given as

y = v_y t + \frac{1}{2}a_y t^2

y = (-15.5)(14) + \frac{1}{2}(-28)(14^2)

y = -2961 m

so the magnitude of the displacement is given as

d = \sqrt{x^2 + y^2}

d = \sqrt{2002^2 + 2961^2}

d = 3574.3 m

7 0
4 years ago
Science Tolliver
Nookie1986 [14]

Answer:

Objects; waves.

Explanation:

Waves interact with objects and other waves. Thus, waves are used on objects such as mobile phones and can be transformed from one form to another.

There are various types of waves in our physical environment such as gamma rays, x-rays, ultraviolet waves, radio waves etc.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data. Some examples of communication technologies that uses radio waves are radio set, mobile phones, television etc.

6 0
3 years ago
A collision at 30 mph will take any loose object in your car and give it the same force as if it were:
Sauron [17]
The answer is “Thrown”
7 0
3 years ago
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