Answer:
A: T = 120 N
B: T = 88.42 N
C: T = 70 N
Explanation:
Part A:
Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.
<u>T = 120 N</u>
<u></u>
Part B:
This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:
T = (2 m₁m₂g)/(m₁+m₂)
where,
m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg
m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg
g = 9.8 m/s²
Therefore,
T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)
T = 1713.6 N.kg/19.38 kg
<u>T = 88.42 N</u>
<u></u>
Part C:
Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.
<u>T = 70 N</u>
Answer:
As ailtitudes rises air pressure drops ...... As altitude increases , the amount of gas molecules in the air decreases - so the air becomes less dense than air nearer to the sea level. So there is less air pressure at high altitudes
Below are the choices that can be found from other source:
a. 0.3 AU
<span>b. 3.8 AU </span>
<span>c. 30 AU </span>
<span>d. 3 million AU
</span>
Answer is c. 30 AU.
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Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J