Answer:
±1, ±2, and ±4
Step-by-step explanation:
4x² + bx + c = (Ax + B) (Cx + D)
Distribute:
4x² + bx + c = ACx² + (AD + BC) x + BD
Matching the coefficients, AC = 4. So A must be a factor of 4. Possible values of A are therefore ±1, ±2, and ±4.
Answer:
24.5/25
Step-by-step explanation:
49/50 divided by 2 is 24.5/25
May not be correct but that's what I got
So I'd say 1%
<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Herro
..............The answer is 15
:)