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2 years ago

7th grade math I will give brainliest to right answer 6 = -4/5 s what is the value of s

Mathematics

1 answer:

alekssr [168]2 years ago

8 0

Answer:

$\frac{-4}{5} s = 6\\-4s = 6*5\\-4s = 30\\s = \frac{30}{-4}$

s = 30/-4 or -7.5

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pochemuha

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3 years ago

andy earned $38 on monday and $34 on tuesday.how many lucky bamboo plants can he buy with the total money he earned?

solong [7]

How much does each bamboo plant cost. This is impossible to solve without knowing the cost. I you have the cost i would be happy to help.

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3 years ago

The sutton police department must write, on average, 6 tickets a day to keep department revenues at budgeted levels. suppose the

lakkis [162]

The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
$P(k \, events) = e^{-\lambda } ( \frac{\lambda ^{k}}{k!} )$

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
$P(k \, tickets/day)=e^{-6.5} ( \frac{6.5 ^{k}}{k!} )$
The distribution is graphed as shown below.

Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.

8 0

3 years ago

If someone eats 3/4 of granola bars per week, what fraction of a box do they eat in per day ?

shepuryov [24]

Answer:

in a day (3/4)÷7=3/28

in a year (3/28)×365=39.107

4 0

2 years ago

The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati

Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0

3 years ago