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2 years ago

7th grade math I will give brainliest to right answer 6 = -4/5 s what is the value of s

Mathematics

1 answer:

alekssr [168]2 years ago

8 0

Answer:

$\frac{-4}{5} s = 6\\-4s = 6*5\\-4s = 30\\s = \frac{30}{-4}$

s = 30/-4 or -7.5

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Carey needs $60 to buy her mother’s a gift. She saved 25% of that amount so far. How much has she saved so far?

sdas [7]

Answer:

Step-by-step explanation:

25% of $60 is:

25*60/100 = 15

She saved $15 so far

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3 years ago

The solution set of 4x-(x+7)=2(x+3)

maria [59]

Step-by-step explanation:

<h3>To Solve:-</h3>

$\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)$

<h3>SOLUTION:-</h3>

$\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)$

$\\ \tt{:}\leadsto 4x-x-7=2x+6$

$\\ \tt{:}\leadsto 3x-7=2x+6$

$\\ \tt{:}\leadsto 3x-2x=6+7$

$\\ \tt{:}\leadsto x=13$

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2 years ago

A ship leaves port on a bearing of 34.0 and travels 10.4 mi. the ship then turns due east and travels 4.6mi. how far is the ship

Natasha2012 [34]

A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)

The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi

the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles

It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°

6 0

3 years ago

Javon is helping his dad build a tree house. He has a piece of trim that is 11 feet long.

posledela

Answer:

Step-by-step explanation:

1 yard = 3 feet

11 feet * (1 yard)/(3 feet) =11/3 yards = 3⅔ yards

Javon can cut three one-yard pieces. ⅔ yard is left over.

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3 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is A. 5y^6

$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is D. 12xy^2

$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

3 0

3 years ago