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kotykmax [81]
2 years ago
7

Problem 3.10 One/half million parts of a certain type are to be manufactured annually on dedicated production machines that run

16 hours per day, five days per week, 50 weeks per year. (a) The cycle time to produce one part is 1.8 min. If availability and utilization are each 100%, and setup time is neglected, how many of the machines will be required to satisfy demand? (b) Solve part (a) except that availability = 95%.
Engineering
2 answers:
goldenfox [79]2 years ago
8 0

Answer:

  • 4 machines
  • 4 machines

Explanation:

(a) The production schedule is 4000 hour per year, or 240,000 minutes. In that time, 133,333 1/3 parts can be produced. The production of 500,000 parts in a year will require the use of ...

  .5 million/(.1333... million/machine) = 3.75 machines

The demand can be satisfied by 4 machines.

__

(b) If availability is 95% then 3.75/0.95 ≈ 3.95 machines will be required.

The demand can be satisfied by 4 machines.

sesenic [268]2 years ago
7 0

Answer:

  • 4 machines
  • 4 machines

A.

B

➡ are both in 4 machines used in

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Answer:

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Compute the theoretical density of ZnS given that the Zn-S distance and bond angle are 0.234 nm and 109.5o, respectively. The at
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first the image of one set of ZnS bonding in the crystal structure, we calculate the value of angle θ

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θ = 90° - ( 109.5° / 2 )

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n' = 8 × 1/8) + ( 6 × 1/2)

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so we substitute

P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)]

= 389.88 / 94.84

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therefore the theoretical density is 4.1109 g/cm³

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