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Lady bird [3.3K]
3 years ago
6

Never get any closer then _____ feet when a train is passing through a railroad crossing. 25 30 15 20

Mathematics
2 answers:
nekit [7.7K]3 years ago
3 0

It totally depends on speed at which train is moving.

If the speed of train is below 100 miles per hour the minimum distance maintained should be 4 feet.

If the speed of train is above 100 miles per hour and less than 125 miles per hour the minimum distance maintained should be  6.6 feet.(Approx)

As , when a train is moving with velocity more than this i.e above 125 miles per hour the minimum distance should be 15 feet.(Approximately)

Option (C) 15



Aleksandr [31]3 years ago
3 0
The answer is 15 feet.
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There are 43 magic beans althogether

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3 years ago
What is the median set of this data set 22 37 49 15 72
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Answer:37

Step-by-step explanation:

first you put them in order from least to greatest

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6 0
2 years ago
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Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?
Tema [17]

Answer:

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Step-by-step explanation:

We are given that

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g(x)=x^2+8

We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

g(y)=y^2+8

Now,

f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)

f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

5 0
2 years ago
Officer Brimberry wrote 32 tickets for traffic violations last week, but only 12 tickets this week. What is the percent decrease
kolbaska11 [484]

Answer:

62.5 %

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4 0
2 years ago
OPEN ENDED QUESTION
posledela

Answer: I hope this helps :)

Substitution:  45+15(6-1)

Simplify:  120

Step-by-step explanation:

Calculate within parenthases (6-1) =5    =45+15(5)

Multiply left to right 15(5)=75      =45+75

Add leftg to right 45+75=120

Answer = 120

4 0
3 years ago
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